Identify the reaction order from each of the following rate constants k = 3 × 10 - 5 s - [Hint. The order of a reaction can be identified from the units given for each value of k.]

The order of the reaction can be determined by the unit of rate constant, which is given by: k = mol L 1 - n time - 1 where n is the value of order of reaction. For first-order reaction n = 1 , So k = mol L 1 - 1 time - 1 k = mol L 0 time - 1 k = time - 1 Thus, given in the question that k = 3 × 10 - 5 s - Here, the rate constant k is only expressed with respect to time s - So, it is the first-order reaction.

Identify the reaction order from each of the following rate constants k = 9 × 10 - 4 mol - 1 litre s - [Hint. The order of a reaction can be identified from the units given for each value of k.]

The order of the reaction can be determined by the unit of rate constant, which is given by: k = mol L 1 - n time - 1 where n is the value of order of reaction. For the second-order reaction n = 2 , So k = mol L 1 - 2 time - 1 k = mol L - 1 time - 1 k = mol - 1 L time - 1 Thus, given in the question that k = 9 × 10 - 4 mol - 1 litre s - Here, the rate constant k is expressed with respect to mol - 1 litre s - 1 So, it is the second-order reaction.

Identify the reaction order from each of the following rate constants k = 6 × 10 - 2 litre mol - s - [Hint. The order of a reaction can be identified from the units given for each value of k.]

The order of the reaction can be determined by the unit of rate constant, which is given by: k = mol L 1 - n time - 1 where n is the value of order of reaction. For the second-order reaction n = 2 , So k = mol L 1 - 2 time - 1 k = mol L - 1 time - 1 k = mol - 1 L time - 1 Thus, given in the question that k = 6 × 10 - 2 litre mol - s - Here, the rate constant k is expressed with respect to litre mol - s - . So, it is a second-order reaction.

Identify the reaction order from each of the following rate constants k = 2 . 3 × 10 - 5 L mol - 1 s - 1 [Hint. The order of a reaction can be identified from the units given for each value of k.]

The order of the reaction can be determined by the unit of rate constant, which is given by: k = mol L 1 - n time - 1 where n is the value of order of reaction. For the second-order reaction n = 2 , So k = mol L 1 - 2 time - 1 k = mol L - 1 time - 1 k = mol - 1 L time - 1 Thus, given in the question that k = 2 . 3 × 10 - 5 L mol - 1 s - 1 Here, the rate constant k is expressed with respect to mol - 1 L s - 1 So, it is a second-order reaction.

Identify the reaction order from each of the following rate constants 3 × 10 - 3 mol L - 1 s - 1 [Hint. The order of a reaction can be identified from the units given for each value of k.]

The order of the reaction can be determined by the unit of rate constant, which is given by: k = mol L 1 - n time - 1 where n is the value of order of reaction. For zero-order reaction, n = 0 ∴ k = mol L 1 - 0 time - 1 k = mol L 1 time - 1 k = mol L - 1 time - 1 Thus, given in the question that k = 3 × 10 - 3 mol L - 1 s - 1 Here, the rate constant k is expressed with respect to mol L - 1 s - 1 . Thus, it is a zero-order reaction.

E M B I B E

NEW SYSTEMATIC MODERN CHEMISTRY>Chapter 4 - Chemical Kinetics>Follow Up Problems

K L Chugh Solutions for Chapter: Chemical Kinetics, Exercise 2: Follow Up Problems

Author:K L Chugh

K L Chugh Chemistry Solutions for Exercise - K L Chugh Solutions for Chapter: Chemical Kinetics, Exercise 2: Follow Up Problems

Attempt the practice questions on Chapter 4: Chemical Kinetics, Exercise 2: Follow Up Problems with hints and solutions to strengthen your understanding. NEW SYSTEMATIC MODERN CHEMISTRY solutions are prepared by Experienced Embibe Experts.