Predict the possibility of occurrence of the following reactions: Zn + 2 H + ⟶ Zn 2 + + H 2 Electrode Standard reduction Potential ( E Θ in volts) Zn 2 + / Zn - 0 . 76 2 H + / H 2 0 . 00

According to the electrochemical series, All metals with lower standard reduction potential are stronger reducing agents than hydrogen. So, they liberate hydrogen from the aqueous solutions of acids. And given, the E ° of Zn < E ° of H 2 Therefore, zinc liberates hydrogen from a dilute solution of acid and the given reaction, Zn + 2 H + ⟶ Zn 2 + + H 2 is feasible or possible.

Predict the possibility of occurrence of the following reactions: 2 Ag + 2 H + ⟶ 2 Ag + + H 2 Electrode Standard reduction Potential ( E Θ in volts) Ag + / Ag + 0 . 80 2 H + / H 2 0 . 00

According to the electrochemical series, All metals with lower standard reduction potential are stronger reducing agents than hydrogen. So, they liberate hydrogen from the aqueous solutions of acids. And given, the E ° of Ag > E ° of H 2 Therefore, silver does not liberate hydrogen from a dilute solution of acid and the given reaction, 2 Ag + 2 H + ⟶ 2 Ag + + H 2 is not feasible or not possible.

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NEW SYSTEMATIC MODERN CHEMISTRY>Chapter 3 - Electrochemistry>Follow Up Problems

K L Chugh Solutions for Chapter: Electrochemistry, Exercise 4: Follow Up Problems

Author:K L Chugh

K L Chugh Chemistry Solutions for Exercise - K L Chugh Solutions for Chapter: Electrochemistry, Exercise 4: Follow Up Problems

Attempt the practice questions on Chapter 3: Electrochemistry, Exercise 4: Follow Up Problems with hints and solutions to strengthen your understanding. NEW SYSTEMATIC MODERN CHEMISTRY solutions are prepared by Experienced Embibe Experts.