The following graph shows the movement of a taxi in city traffic during a 4 - hour period. Clearly and concisely describe the taxi's journey.

The graph that shows the connection between the distance an object has travelled and the time taken to travel that distance is called distance-time graph. Here, we have In this graph the distance travelled by a car and time taken of its journey is given. The line of the graph remains horizontal while the car was not moving or the car was waiting for passenger. Here, the taxi travelled a distance of 10 km in 50 minutes. So, speed of the taxi = Distance Time = 10 50 60 = 12 km / hr Then after stationary position, it travelled back 10 km in 20 minutes. So, speed of the taxi while coming back = 10 20 60 = 30 km / hr Thus, we get for the first 50 minutes the taxi travelled a distance of 10 km at 12 km / hr , then was stationary for 50 minutes then took 20 minutes to return to starting point at 30 km / hr . The taxi was then stationary for 40 minutes, then travelled 5 km in 40 minutes at a speed of 7 . 5 km / hr and was then stationary for 40 minutes.

The following graph shows the movement of a taxi in city traffic during a 4 - hour period. For how many minutes was the taxi waiting for passenger in this period.

The graph that shows the connection between the distance an object has travelled and the time taken to travel that distance is called distance-time graph. Here, we have In this graph the distance travelled by a car and time taken of its journey is given. The line of the graph remains horizontal while the car was not moving or the car was waiting for passenger. For the first 50 minutes the taxi travelled a distance of 10 km then was stationary for 50 minutes then took 20 minutes to return to starting point. The taxi was then stationary for 40 minutes, then travelled 5 km in 40 minutes and was then stationary for 40 minutes. So, the total time the taxi was waiting for passenger = 50 + 40 + 40 = 130 minutes.

The following graph shows the movement of a taxi in city traffic during a 4 - hour period. Calculate the taxis's average speed during the first 20 minutes.

The graph that shows the connection between the distance an object has travelled and the time taken to travel that distance is called distance-time graph. Here, we have In this graph the distance travelled by a car and time taken of its journey is given. The line of the graph remains horizontal while the car was not moving or the car was waiting for passenger. Here, the taxi travelled a distance of 4 km in 20 minutes. So, speed of the taxi = Distance Time = 4 20 60 = 12 km / hr

The following graph shows the movement of a taxi in city traffic during a 4 - hour period. Calculate the taxis's average speed during the first hour.

The graph that shows the connection between the distance an object has travelled and the time taken to travel that distance is called distance-time graph. Here, we have In this graph the distance travelled by a car and time taken of its journey is given. The line of the graph remains horizontal while the car was not moving or the car was waiting for passenger. For the first 50 minutes the taxi travelled a distance of 10 km , then was stationary for 50 minutes. For first 20 minutes the average speed = 4 20 60 = 12 km / hr For, next 20 minutes the average speed = 12 km / hr For, next 20 minutes the average speed = 2 20 60 = 6 km / hr So, the average speed for first hour = 12 + 12 + 6 3 = 10 km / hr Hence, the answer is 10 km / hr .

The following graph shows the movement of a taxi in city traffic during a 4 - hour period. Calculate the taxis's average speed from 160 - 210 minutes.

The graph that shows the connection between the distance an object has travelled and the time taken to travel that distance is called distance-time graph. Here, we have In this graph the distance travelled by a car and time taken of its journey is given. The line of the graph remains horizontal while the car was not moving or the car was waiting for passenger. The taxi after stationary position, it travelled 5 km during 160 - 210 minutes. So, the average speed = Distance Time = 5 50 60 = 6 km / hr

The following graph shows the movement of a taxi in city traffic during a 4 - hour period. Calculate the taxis's average speed for the full period of the graph.

The graph that shows the connection between the distance an object has travelled and the time taken to travel that distance is called distance-time graph. Here, we have In this graph the distance travelled by a car and time taken of its journey is given. The line of the graph remains horizontal while the car was not moving or the car was waiting for passenger. Thus, we get for the first 50 minutes the taxi travelled a distance of 10 km , then was stationary for 50 minutes then took 20 minutes to return to starting. The taxi was then stationary for 40 minutes, then travelled 5 km in 40 minutes. So, total distance covered by the taxi = 10 + 10 + 5 = 25 km Total time taken to cover the distance = 200 minutes. So, the average speed of the taxi = 25 200 = 0 . 125 km / hr

Karen Morrison and Nick Hamshaw Solutions for Exercise 7: Exercise 21.7

Author:Karen Morrison & Nick Hamshaw

Karen Morrison Mathematics Solutions for Exercise - Karen Morrison and Nick Hamshaw Solutions for Exercise 7: Exercise 21.7

Attempt the practice questions from Exercise 7: Exercise 21.7 with hints and solutions to strengthen your understanding. Cambridge IGCSE® Mathematics Core and Extended Coursebook Second Edition solutions are prepared by Experienced Embibe Experts.

Questions from Karen Morrison and Nick Hamshaw Solutions for Exercise 7: Exercise 21.7 with Hints & Solutions

MEDIUM

Upper Secondary: IGCSE

IMPORTANT

Cambridge IGCSE® Mathematics Core and Extended Coursebook Second Edition>Chapter 21 - Ratio, Rate and Proportion>Exercise 21.7>Q 3

The following graph shows the movement of a taxi in city traffic during a $4 -$ hour period.

Question Image

Clearly and concisely describe the taxi's journey.

MEDIUM

Upper Secondary: IGCSE

IMPORTANT

Cambridge IGCSE® Mathematics Core and Extended Coursebook Second Edition>Chapter 21 - Ratio, Rate and Proportion>Exercise 21.7>Q 3

The following graph shows the movement of a taxi in city traffic during a $4 -$ hour period.

Question Image

For how many minutes was the taxi waiting for passenger in this period.

MEDIUM

Upper Secondary: IGCSE

IMPORTANT

Cambridge IGCSE® Mathematics Core and Extended Coursebook Second Edition>Chapter 21 - Ratio, Rate and Proportion>Exercise 21.7>Q 3

The following graph shows the movement of a taxi in city traffic during a $4 -$ hour period.

Question Image

What was the total distance travelled?

EASY

Upper Secondary: IGCSE

IMPORTANT

Cambridge IGCSE® Mathematics Core and Extended Coursebook Second Edition>Chapter 21 - Ratio, Rate and Proportion>Exercise 21.7>Q 3

The following graph shows the movement of a taxi in city traffic during a $4 -$ hour period.

Question Image

Calculate the taxis's average speed during the first $20$ minutes.

EASY

Upper Secondary: IGCSE

IMPORTANT

Cambridge IGCSE® Mathematics Core and Extended Coursebook Second Edition>Chapter 21 - Ratio, Rate and Proportion>Exercise 21.7>Q 3

The following graph shows the movement of a taxi in city traffic during a $4 -$ hour period.

Question Image

Calculate the taxis's average speed during the first hour.

EASY

Upper Secondary: IGCSE

IMPORTANT

Cambridge IGCSE® Mathematics Core and Extended Coursebook Second Edition>Chapter 21 - Ratio, Rate and Proportion>Exercise 21.7>Q 3

The following graph shows the movement of a taxi in city traffic during a $4 -$ hour period.

Question Image

Calculate the taxis's average speed from $160 - 210$ minutes.

EASY

Upper Secondary: IGCSE

IMPORTANT

Cambridge IGCSE® Mathematics Core and Extended Coursebook Second Edition>Chapter 21 - Ratio, Rate and Proportion>Exercise 21.7>Q 3

The following graph shows the movement of a taxi in city traffic during a $4 -$ hour period.

Question Image

Calculate the taxis's average speed for the full period of the graph.

MEDIUM

Upper Secondary: IGCSE

IMPORTANT

Cambridge IGCSE® Mathematics Core and Extended Coursebook Second Edition>Chapter 21 - Ratio, Rate and Proportion>Exercise 21.7>Q 4

This is a real distance-time graph showing distance from the ground against time for a helicopter as it takes off and flies away from an airport.

Question Image

Make up five mathematical questions that can be answered from the graph.

Karen Morrison and Nick Hamshaw Solutions for Exercise 7: Exercise 21.7

Karen Morrison Mathematics Solutions for Exercise - Karen Morrison and Nick Hamshaw Solutions for Exercise 7: Exercise 21.7

Questions from Karen Morrison and Nick Hamshaw Solutions for Exercise 7: Exercise 21.7 with Hints & Solutions

Learn and Prepare for any exam you want !