Kerala Board Solutions for Chapter: Redox Reactions and Rate of Chemical Reactions, Exercise 1: Exercise 1

Analyse the following reaction:

$2\stackrel{0}{\mathrm{Na}}+\stackrel{0}{{\mathrm{Cl}}_2}\to 2\stackrel{+1}{\mathrm{Na}}\stackrel{-1}{\mathrm{C}}\mathrm{l}$

Oxidation number of which atom is increased?

Analyse the following reaction:

$2\stackrel{0}{\mathrm{Na}}+\stackrel{0}{{\mathrm{Cl}}_2}\to 2\stackrel{+1}{\mathrm{Na}}\stackrel{-1}{\mathrm{C}}\mathrm{l}$

The oxidised atom is _____.

Analyse the following reaction:

$2\stackrel{0}{\mathrm{Na}}+\stackrel{0}{{\mathrm{Cl}}_2}\to 2\stackrel{+1}{\mathrm{Na}}\stackrel{-1}{\mathrm{C}}\mathrm{l}$

Oxidation number of which atom is decreased?

Analyse the following reaction:

$2\stackrel{0}{\mathrm{Na}}+\stackrel{0}{{\mathrm{Cl}}_2}\to 2\stackrel{+1}{\mathrm{Na}}\stackrel{-1}{\mathrm{C}}\mathrm{l}$

The reduced atom is_____.

Analyse the following reaction:

$2\stackrel{0}{\mathrm{Na}}+\stackrel{0}{{\mathrm{Cl}}_2}\to 2\stackrel{+1}{\mathrm{Na}}\stackrel{-1}{\mathrm{C}}\mathrm{l}$

The Oxidising agent is_____.

Analyse the following reaction:

$2\stackrel{0}{\mathrm{Na}}+\stackrel{0}{{\mathrm{Cl}}_2}\to 2\stackrel{+1}{\mathrm{Na}}\stackrel{-1}{\mathrm{C}}\mathrm{l}$

The reducing agent is_____.

Consider the equation and answer the following question:

$\stackrel{0}{\mathrm{Zn}}+2\stackrel{+1}{\mathrm{H}}\stackrel{-1}{\mathrm{Cl}}\to \stackrel{+2}{\mathrm{Zn}}\stackrel{-1}{{\mathrm{Cl}}_2}+\stackrel{0}{{\mathrm{H}}_2}$

The oxidized atom is_____.

Consider the equation and answer the following question:

$\stackrel{0}{\mathrm{Zn}}+2\stackrel{+1}{\mathrm{H}}\stackrel{-1}{\mathrm{Cl}}\to \stackrel{+2}{\mathrm{Zn}}\stackrel{-1}{{\mathrm{Cl}}_2}+\stackrel{0}{{\mathrm{H}}_2}$

 The reduced atom is _____.