Name: Word Problem on Subtraction
Uploaded: 2019-07-19
Duration: 3 min 21 s
Description: If you don't want to go through your books to solve subtraction word problems, you are in the right place. Watch this video to see subtraction broken down in...

Question

Check whether the equation $- x + (x + 1) = 1$ holds for $x = 1, 2, 3, 4, 5$ and $x = - 1, - 2, - 3, - 4, - 5$ .

Accepted Answer

Given: $- x + (x + 1) = 1$

$x = 1, 2, 3, 4, 5$ and $x = - 1, - 2, - 3, - 4, - 5$

We need to check whether the equation holds for all the given $x$ values.

Now, put $x = 1$ in $- x + (x + 1) = 1$ and verify.

Thus, $- 1 + (1 + 1) = 1$

$\Rightarrow - 1 + 2 = 1$

$\Rightarrow 1 = 1$

Here, $LHS = RHS$

Now, put $x = 2$ in $- x + (x + 1) = 1$ and verify.

Thus, $- 2 + (2 + 1) = 1$

$\Rightarrow - 2 + 3 = 1$

$\Rightarrow 1 = 1$

Here, $LHS = RHS$

Now, put $x = 3$ in $- x + (x + 1) = 1$ and verify.

Thus, $- 3 + (3 + 1) = 1$

$\Rightarrow - 3 + 4 = 1$

$\Rightarrow 1 = 1$

Here, $LHS = RHS$

Now, put $x = 4$ in $- x + (x + 1) = 1$ and verify.

Thus, $- 4 + (4 + 1) = 1$

$\Rightarrow - 4 + 5 = 1$

$\Rightarrow 1 = 1$

Here, $LHS = RHS$

Now, put $x = 5$ in $- x + (x + 1) = 1$ and verify.

Thus, $- 5 + (5 + 1) = 1$

$\Rightarrow - 5 + 6 = 1$

$\Rightarrow 1 = 1$

Here, $LHS = RHS$

Now, put $x = - 1$ in $- x + (x + 1) = 1$ and verify.

Thus, $- (- 1) + (- 1 + 1) = 1$

$\Rightarrow 1 + 0 = 1$

$\Rightarrow 1 = 1$

Here, $LHS = RHS$

Now, put $x = - 2$ in $- x + (x + 1) = 1$ and verify.

Thus, $- (- 2) + (- 2 + 1) = 1$

$\Rightarrow 2 - 1 = 1$

$\Rightarrow 1 = 1$

Here, $LHS = RHS$

Now, put $x = - 3$ in $- x + (x + 1) = 1$ and verify.

Thus, $- (- 3) + (- 3 + 1) = 1$

$\Rightarrow 3 - 2 = 1$

$\Rightarrow 1 = 1$

Here, $LHS = RHS$

Now, put $x = - 4$ in $- x + (x + 1) = 1$ and verify.

Thus, $- (- 4) + (- 4 + 1) = 1$

$\Rightarrow 4 - 3 = 1$

$\Rightarrow 1 = 1$

Here, $LHS = RHS$

Now, put $x = - 5$ in $- x + (x + 1) = 1$ and verify.

Thus, $- (- 5) + (- 5 + 1) = 1$

$\Rightarrow 5 - 4 = 1$

$\Rightarrow 1 = 1$

Here, $LHS = RHS$

Hence, the equation $- x + (x + 1) = 1$ holds for all the given $x$ values.

Kerala Board Solutions for Chapter: Negative Numbers, Exercise 3: Check whether this equation holds for all kinds of numbers

Kerala Board Mathematics Solutions for Exercise - Kerala Board Solutions for Chapter: Negative Numbers, Exercise 3: Check whether this equation holds for all kinds of numbers

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