Kerala Board Solutions for Chapter: Negative Numbers, Exercise 4: Exercise 4

In the equation $y=x^2+3x+2$, take $x=-2$ and compute the value of $y$.

In the equation $y=x^2+5x+4$, take $x=-2$, $x=-3$ and compute the values of $y$.

In the equation $y=x^3+1$, take $x=-1$ and compute the value of $y$.

In the equation $y=x^3+x^2+x+1$, take $x=-1$ and compute the value of $y$.

For a point starting at a point $P$ and travelling along a straight line, time of travel is taken as$t$and the distance from $P$ as $s$. The relation between $s$ and $t$ is found to be $s=12t-2t^2$, where distances to the right are taken as positive numbers and to the left as negative numbers.

Is the position of the point to the right or left of$P$, till $6$ $\mathrm{seconds}$?

For a point starting at a point $P$ and travelling along a straight line, time of travel is taken as$t$and the distance from $P$ as $s$. The relation between $s$ and $t$ is found to be $s=12t-2t^2$, where distances to the right are taken as positive numbers and to the left as negative numbers. Where is the position at $6$ seconds?

For a point starting at a point P and travelling along a straight line, time of travel is taken as $t$ and the distance from $P$ as $s$. The relation between $s$ and $t$ is found to be $s=12t-2t^2$ where distances to the right are taken as positive numbers and to the left as negative numbers. After $6$ $\mathrm{seconds}$?

Natural numbers, their negatives and zero are together called integers. How many pairs of integers are there, satisfying the equation, $x^2+y^2=25$?