Fill in the blank boxes correctly. Combinations of 3 . Number: 3 The number of combinations: 4 ⋱ + = ⋱ = 3 + 0 = 3 · · + · = ⋱ = 2 + 1 = · + · · = ⋱ = 1 + = + ⋱ = ⋱ = 0 + =

Given, ⋱ + = ⋱ = 3 + 0 = 3 · · + · = ⋱ = 2 + 1 = · + · · = ⋱ = 1 + = + ⋱ = ⋱ = 0 + = Here, we need to fill the boxes by using the number combinations of the number 3 . The combination of number 3 means, we have to make the sum as 3 by taking different combinations of numbers. ⋱ + = ⋱ = 3 + 0 = 3 · · + · = ⋱ = 2 + 1 = 3 · + · · = ⋱ = 1 + 2 = 3 + ⋱ = ⋱ = 0 + 3 = 3 Hence, combination of 3 is shown in above table.

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Destination Maths 1>Chapter 2 - Addition up to 20>Exercise 7

Kusum Wadhwa and Anju Loomba Solutions for Chapter: Addition up to 20, Exercise 7: Exercise 7

Author:Kusum Wadhwa & Anju Loomba

Kusum Wadhwa Mathematics Solutions for Exercise - Kusum Wadhwa and Anju Loomba Solutions for Chapter: Addition up to 20, Exercise 7: Exercise 7

Attempt the free practice questions on Chapter 2: Addition up to 20, Exercise 7: Exercise 7 with hints and solutions to strengthen your understanding. Destination Maths 1 solutions are prepared by Experienced Embibe Experts.

Questions from Kusum Wadhwa and Anju Loomba Solutions for Chapter: Addition up to 20, Exercise 7: Exercise 7 with Hints & Solutions

HARD

1st CBSE

IMPORTANT

Destination Maths 1>Chapter 2 - Addition up to 20>Exercise 7

Fill in the blank boxes correctly.

Combinations of $3$ .

Number: $=$

The number of combinations: $3$

$⋱$	$+$		$=$	$⋱$	$=$	$3$	$+$	$0$	$=$	$3$
$\cdot \cdot$	$+$	$\cdot$	$=$	$⋱$	$=$	$2$	$+$	$1$	$=$
$\cdot$	$+$	$\cdot \cdot$	$=$	$⋱$	$=$	$1$	$+$		$2$
	$+$	$⋱$	$=$	$⋱$	$=$	$0$	$+$		$=$

HARD

1st CBSE

IMPORTANT

Destination Maths 1>Chapter 2 - Addition up to 20>Exercise 7

Fill in the blank boxes correctly.

Combination of $4$ .

Number: $4$

The number of combinations: $5$

$\cdot \cdot \cdot \cdot$	$+$		$=$	$\cdot \cdot \cdot \cdot$	$=$	$4$	$+$	$0$	$=$	$4$
$⋱$	$+$	$\cdot$	$=$	$\cdot \cdot \cdot \cdot$	$=$	$3$	$+$	$1$	$=$	$4$
$\cdot \cdot$	$+$	$\cdot \cdot$	$=$	$\cdot \cdot \cdot \cdot$	$=$	$2$	$+$	$2$	$=$
$\cdot$	$+$	$⋱$	$=$	$\cdot \cdot \cdot \cdot$	$=$	$1$	$+$		$=$
	$+$	$\cdot \cdot \cdot \cdot$	$=$	$\cdot \cdot \cdot \cdot$	$=$	$0$	$+$		$=$