Lakhmir Singh and Manjit Kaur Solutions for Chapter: Refraction of Light, Exercise 19: Multiple Choice Questions (MCQs)

A convex lens produces a magnification of $+5$. The object is placed:

If a magnification of, $-1 \left(\mathrm{minus} 1\right)$ is obtained by using a converging lens, then the object has to be placed:

To obtain a magnification of, $-0.5$ with a convex lens, the object should be placed:

An object is $0.09 \mathrm{m}$ from a magnifying lens and the image is formed $36 \mathrm{cm}$ from the lens. The magnification produced is:

To obtain a magnification of, $-2$ with a convex lens of focal length $10 \mathrm{cm}$, the object should be placed:

A convex lens of focal length $15 \mathrm{cm}$ produces a magnification of $+4$. The object is placed:

If a magnification of $-1$ is to be obtained by using a converging lens of focal length $12 \mathrm{cm}$, then the object must be placed:

In order to obtain a magnification of, $-0.75$ with a convex lens of focal length $8 \mathrm{cm}$, the object should be placed