Lawrie Ryan and Roger Norris Solutions for Chapter: Entropy and Gibbs Free Energy, Exercise 8: Question

Author:Lawrie Ryan & Roger Norris

Lawrie Ryan Chemistry Solutions for Exercise - Lawrie Ryan and Roger Norris Solutions for Chapter: Entropy and Gibbs Free Energy, Exercise 8: Question

Attempt the free practice questions on Chapter 23: Entropy and Gibbs Free Energy, Exercise 8: Question with hints and solutions to strengthen your understanding. Chemistry for Cambridge International AS & A Level Coursebook with Digital Access (2 Years) solutions are prepared by Experienced Embibe Experts.

Questions from Lawrie Ryan and Roger Norris Solutions for Chapter: Entropy and Gibbs Free Energy, Exercise 8: Question with Hints & Solutions

EASY
AS and A Level
IMPORTANT

Calculate the total entropy change in each of the following reactions using the standard molar entropy values given here.

Values for:

 S in J K-1 mol-1.Given:Ss=31.80H2g=130.6H2Sg=205.7Ss+H2gH2Sg; Hreaction=-20.6 kJ mol-1.

EASY
AS and A Level
IMPORTANT

Calculate the total entropy change in each of the following reactions using the standard molar entropy values given here.

Values for

 S in J K-1 mol-1.Given:Cgraphite=5.700N2g=191.6C2N2g=242.12Cgraphite+N2gC2N2g; Hreaction=+307.9 kJ mol-1.

EASY
AS and A Level
IMPORTANT

Calculate the total entropy change in each of the following reactions using the standard molar entropy values given here.

Values for

S in J K-1 mol-1.Given:Ps=41.10O2g=205.0P4O10s=228.94Ps+5O2gP4O10s; Hreaction=-2984.0 kJ mol-1.

EASY
AS and A Level
IMPORTANT

Calculate the total entropy change in each of the following reactions using the standard molar entropy values given here.

Values for

S in J K-1 mol-1.Given:C3H8g=269.9O2g=205.0CO2g=213.6H2Ol=69.90C3H8g+5O2g3CO2g+4H2Ol; Hreaction=-2219.2 kJ mol-1.