M L Aggarwal Solutions for Exercise 4: Exercise 9.4

Find the next term of the list of numbers $\frac{1}{6}, \frac{1}{3}, \frac{2}{3}, ......$

Find the next term of the list of numbers $\frac{3}{16},-\frac{3}{8}, \frac{3}{4},-\frac{3}{2},......$

Find the $10\mathrm{th}$ and $\mathrm{nth}$ terms of the list of numbers: $5, 25, 125, .......$

Find the $6\mathrm{th}$ term from the end of the list of numbers: $3,-6,12,-24,.......,12288$.

Which term of G.P. $1, \frac{1}{3}, \frac{1}{9}, .....$ is $\frac{1}{243}$?

Determine the ${12}^{th}$ term of the G.P. whose $8^{th}$term is $192$ and the common ratio is $2.$

In a G.P., the third term is $24$ and $6\mathrm{th}$ term is $192$. Find the $10\mathrm{th}$ term.

Find the value of $x$ such that $\mathrm{x}, \mathrm{x}+3, \mathrm{x}+9$ are first three terms of a G.P.