Using the standard formulae, expand the following: 2 3 x - 3 2 x - 1 2

Given that 2 x 3 - 3 2 x - 1 2 , comparing it to ( x + y + z ) 2 , we get x = 2 x 3 , y = - 3 2 x & z = - 1 We know that ( x + y + z ) 2 = x 2 + y 2 + z 2 + 2 ( xy + yz + zx ) ⇒ 2 x 3 - 3 2 x - 1 2 = 2 x 3 2 + - 3 2 x 2 + - 1 2 + 2 × [ 2 x 3 × - 3 2 x + - 3 2 x × - 1 + - 1 × 2 x 3 ] = 4 x 2 9 + 9 4 x 2 + 1 + 2 × - 1 + 3 2 x - 2 x 3 = 4 x 2 9 + 9 4 x 2 + 1 - 2 + 2 × 3 2 x + 2 × - 2 x 3 = 4 x 2 9 + 9 4 x 2 - 1 + 3 x - 4 x 3 Hence, the final answer will be 4 x 2 9 + 9 4 x 2 - 1 + 3 x - 4 x 3

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Understanding ICSE Mathematics Class 9>Algebra>Chapter 3 - Expansions>EXERCISE 3.1

M L Aggarwal Solutions for Exercise 1: EXERCISE 3.1

Author:M L Aggarwal

M L Aggarwal Mathematics Solutions for Exercise - M L Aggarwal Solutions for Exercise 1: EXERCISE 3.1

Attempt the practice questions from Exercise 1: EXERCISE 3.1 with hints and solutions to strengthen your understanding. Understanding ICSE Mathematics Class 9 solutions are prepared by Experienced Embibe Experts.