M L Aggarwal Solutions for Chapter: Conic Sections, Exercise 2: EXERCISE

The equation of directrix of parabola is $x+y=2$ and the focus is $\left(3,-4\right)$. Find the equation of parabola.

Find the equation of the parabola whose vertex is at $\left(-2,2\right)$ and focus is at $\left(-2,6\right)$.

Given that the vertex is at $\left(6,-3\right)$ and directrix is $3x-5y+1=0$, find the focus and the equation of parabola.

Show that the equation $y^2+6y-2x+5=0$  represents the parabola.find its vertex,focus,length of latus rectum,equation of axis and directrix.

Show that the equation$y^2-8y-x+19=0$  represents the parabola. Find its vertex, focus, equation of axis and directrix.

Show that the equation $y=x^2-2x+3$  represents the parabola. Find its vertex, focus, equation of axis and directrix.

Show that the equation $x^2+3x+4y-2=0$  represents the parabola. Find its vertex, focus, equation of axis and directrix.

Show that the equation $x^2+2y-3x+5=0$ represents the parabola. Find its vertex, focus, equation of axis and directrix.