Umakant Kondapure, Collin Fernandes, Nipun Bhatia, Vikram Bathula and, Ketki Deshpande Solutions for Chapter: Magnetism, Exercise 1: Classical Thinking

The magnetic induction due to a bar magnet of length $6\times {10}^{-2} \mathrm{m}$ and pole strength $5\times {10}^{-3} \mathrm{m}$ at a point $0.1 \mathrm{m}$ away from the centre and along the equator is

In order to have a strong electromagnet, it must have,

Earth's magnetic field always has a horizontal component except at

Each pole of a magnet of length $20 \mathrm{cm}$ in a magnetic field of induction $0.2 \mathrm{T}$ experiences a force $20 \mathrm{N}$. The magnetic moment of magnet is

If the moment of a magnet is $0.4 \mathrm{A} {\mathrm{m}}^2$ and force acting on each pole in a uniform magnetic field of induction $3.2\times {10}^{-5} \mathrm{Wb} {\mathrm{m}}^{-2}$ is $5.12\times {10}^{-5} \mathrm{N},$ the distance between the poles of the magnet is

If at a given place the earth's magnetic induction $B$ is $5\times {10}^{-4} \mathrm{T}$ and the horizontal component $B_{\mathrm{H}}$ is $3\times {10}^{-4} \mathrm{T}$, then the vertical component $B_{\mathrm{V}}$ is

The torque acting on a magnetic dipole of moment $5 \mathrm{A} {\mathrm{m}}^2$ when placed in an external uniform magnetic field of induction $1.5\times {10}^{-4} \mathrm{Wb} {\mathrm{m}}^{-2}$ at right angles to magnetic field is

The number of electrons flowing in a current carrying circular coil per second having area of $2 {\mathrm{m}}^2$ and magnetic moment of $8 \mathrm{A} {\mathrm{m}}^2$ is