Umakant Kondapure, Collin Fernandes, Nipun Bhatia, Vikram Bathula and, Ketki Deshpande Solutions for Chapter: Rotational Motion, Exercise 1: Classical Thinking

The relation between the torque $\overrightarrow{\tau }$ and the angular momentum $\overrightarrow{\mathit{L}}$ of a body of moment of inertia $I$ rotating with angular velocity $\omega$ is

The Unit of angular momentum is
 

A constant torque is applied on a circular wheel, which changes its angular momentum from $0$ to  $4 L$ in $4 \mathrm{s}$. The torque is

A uniform stick of length$l$ and mass $m$ lies on a smooth table. It rotates with angular velocity $\omega$ about an axis perpendicular to the table and through one end of the stick. The angular momentum of the stick about the end is

The moment of inertia of a uniform circular disc of mass $M$ and radius $R$ about any of its diameters is $\frac{1}{4}M{R}^2.$ What is the moment of inertia of the disc about an axis passing through its centre and normal to the disc?

The moment of inertia of a body about a given axis is $3.6 \mathrm{kg} {\mathrm{m}}^2$. Initially, the body is at rest. In order to produce a rotational $K.E.$ of $800 \mathrm{J}$, an acceleration of $15$ $\mathrm{rad} {\mathrm{s}}^{-2}$ must be applied about that axis for

A ring, a solid cylinder and a solid sphere roll on the same inclined plane without slipping, starting from rest. The radii of the bodies are identical. Which of the bodies reach the ground with maximum velocity?
 

Assertion: A disc rolls without slipping on a horizontal surface and the linear speed of its centre of mass is $v$. The rotational speed of the particles on its rim at the top of the disc will be $2v$

Reason: The disc rolls as if it is rotating about the point of contact with the horizontal surface.