Question

Draw up a data table using the following headings:

Temperature of the reaction mixture in the conical flask

(° C)

Time taken for the black cross to disappear

(s)

Rate of the reaction

(s^{- 1})

Accepted Answer

The following table is obtained from the experimental data:

Temperature of the reaction mixture in the conical flask $(° C)$

Time taken for the black cross to disappear $(s)$

Rate of the reaction $(s^{- 1})$

$25$

$t_{1}$

$X_{1}$

$35$

$t_{2}$

$X_{2}$

$45$

$t_{3}$

$X_{3}$

$55$

$t_{4}$

$X_{4}$

$65$

$t_{5}$

$X_{5}$

In this table,

$t_{1}$ is the time taken for the completion of the reaction at $25 ° C$ and $X_{1} s^{- 1}$ is the rate of the reaction.

$t_{2}$ is the time taken for the completion of the reaction at $35 ° C$ and $X_{2} s^{- 1}$ is the rate of the reaction.

$t_{3}$ is the time taken for the completion of the reaction at $45 ° C$ and $X_{3} s^{- 1}$ is the rate of the reaction.

$t_{4}$ is the time taken for the completion of the reaction at $55 ° C$ and $X_{4} s^{- 1}$ is the rate of the reaction.

$t_{5}$ is the time taken for the completion of the reaction at $65 ° C$ and $X_{5} s^{- 1}$ is the rate of the reaction.

The value of the time taken for the completion of the reaction is $t_{1} > t_{2} > t_{3} > t_{4} > t_{5}$ and the rate will be $X_{1} < X_{2} < X_{3} < X_{4} < X_{5}$ . Thus, the rate of the reaction is directly proportional to the temperature.

Gary Horner Solutions for Chapter: Conditions, Exercise 14: Experiment

Gary Horner Chemistry Solutions for Exercise - Gary Horner Solutions for Chapter: Conditions, Exercise 14: Experiment

Questions from Gary Horner Solutions for Chapter: Conditions, Exercise 14: Experiment with Hints & Solutions

Learn and Prepare for any exam you want !