Mahabir Singh Solutions for Chapter: Surface Areas and Volumes, Exercise 1: MATHEMATICAL REASONING
Mahabir Singh Mathematics Solutions for Exercise - Mahabir Singh Solutions for Chapter: Surface Areas and Volumes, Exercise 1: MATHEMATICAL REASONING
Attempt the free practice questions on Chapter 13: Surface Areas and Volumes, Exercise 1: MATHEMATICAL REASONING with hints and solutions to strengthen your understanding. IMO Olympiad Work Book 9 solutions are prepared by Experienced Embibe Experts.
Questions from Mahabir Singh Solutions for Chapter: Surface Areas and Volumes, Exercise 1: MATHEMATICAL REASONING with Hints & Solutions
A metal sheet long. broad and thick is melted into a cube. Find the difference between surface areas of two solids.

The height of a cone is equal to its base diameter. Then slant height of the cone is

The length of the longest rod that can be kept in a cuboidal room of dimensions is __________.

A hemispherical bowl is filled to the brim with a beverage. The contents of the bowl are transferred into a cylindrical vessel whose radius is more than its height. If the diameter is same for both the bowl and the cylinder, then the amount of the beverage that can be poured from the bowl into the cylindrical vessel is

The volume of a cylinder of radius is of the volume of rectangular box with a square base of side length . If the cylinder and the box have equal heights, what is the value of in terms of

The edge of a cube is . How many small cubes of edge can be formed from this cube?

The volume of two spheres are in the ratio . the difference of their surface areas, if the sum of their radii is units, is ______

The radii of two cylinders are in the ratio and their heights are in the ratio of The ratio of their volumes is ___________
