Maharashtra Board Solutions for Chapter: Electromagnetic Induction, Exercise 4: Exercises

Author:Maharashtra Board

Maharashtra Board Physics Solutions for Exercise - Maharashtra Board Solutions for Chapter: Electromagnetic Induction, Exercise 4: Exercises

Attempt the practice questions on Chapter 12: Electromagnetic Induction, Exercise 4: Exercises with hints and solutions to strengthen your understanding. Physics Standard 12 solutions are prepared by Experienced Embibe Experts.

Questions from Maharashtra Board Solutions for Chapter: Electromagnetic Induction, Exercise 4: Exercises with Hints & Solutions

EASY
12th Maharashtra Board
IMPORTANT

Two inductor coils with inductance 10 mH and 20 mH are connected in series. What is the resultant inductance of the combination of the two coils?

MEDIUM
12th Maharashtra Board
IMPORTANT

Calculate the value of induced emf between the ends of an axle of a railway carriage 1.75 m long travelling on level ground with a uniform velocity of 50 km per hour. The vertical component of Earth’s magnetic field (B) is given to be 5×10-5T.

EASY
12th Maharashtra Board
IMPORTANT

The value of mutual inductance of two coils is 10 mH. If the current in one of the coil changes from 5A to 1A in 0.2 s, calculate the value of emf induced in the other coil.

EASY
12th Maharashtra Board
IMPORTANT

An emf of 96.0 mV is induced in the windings of a coil when the current in a nearby coil is increasing at the rate of 1.20 A/s. “What is the mutual inductance (M) of the two coils?

HARD
12th Maharashtra Board
IMPORTANT

A long solenoid of length l, cross- sectional area A and having N1 turns (primary coil) has a small coil of N2, turns (secondary coil) wound about its centre. Determine the Mutual inductance (M) of the two coils.

HARD
12th Maharashtra Board
IMPORTANT

The primary and secondary coil of a transformer each have an inductance of 200×10-6 H. The mutual inductance (M) between the windings is 4×10-6 H. What percentage of the flux from one coil reaches the other’?

MEDIUM
12th Maharashtra Board
IMPORTANT

A toroidal ring, having 100 turns per cm of a thin wire is wound on a non- magnetic metal rod of length 1 m and diameter 1 cm. If the permeability of bar is equal to that of free space (μ0), calculate the magnetic field inside the bar (B) when the current (I) circulating through the turns is 1 A. Also determine the self-inductance (L) of the coil.

MEDIUM
12th Maharashtra Board
IMPORTANT

A uniform magnetic field Bt, pointing upward fills a circular region of radius, s in a horizontal plane. If B is changes with time, find the induced electric field.