Maharashtra Board Solutions for Chapter: Probability Distributions, Exercise 3: MISCELLANEOUS EXERCISE 7

Author:Maharashtra Board

Maharashtra Board Mathematics Solutions for Exercise - Maharashtra Board Solutions for Chapter: Probability Distributions, Exercise 3: MISCELLANEOUS EXERCISE 7

Attempt the practice questions on Chapter 7: Probability Distributions, Exercise 3: MISCELLANEOUS EXERCISE 7 with hints and solutions to strengthen your understanding. Mathematics & Statistics (Arts & Science) Part 2 Standard 12 solutions are prepared by Experienced Embibe Experts.

Questions from Maharashtra Board Solutions for Chapter: Probability Distributions, Exercise 3: MISCELLANEOUS EXERCISE 7 with Hints & Solutions

EASY
12th Maharashtra Board
IMPORTANT

The following is the c.d.f of R.V X

X-3-2-101234F(X)0.10.30.50.650.750.850.91

Find P-1X2

EASY
12th Maharashtra Board
IMPORTANT

The following is the c.d.f of R.V X

X-3-2-101234F(X)0.10.30.50.650.750.850.91

Find P(X3X>0)

MEDIUM
12th Maharashtra Board
IMPORTANT

A player tosses two coins he wins  10 if 2 heads appears,  5 if 1 head appears and  2 if no head appears. Find the expected winning amount and variance of winning amount.

MEDIUM
12th Maharashtra Board
IMPORTANT

Let the p.m.f. of r.v. X be Px=3-x10, for x=-1,0,1,2 and =0, otherwise Calculate Ex and VarX.

MEDIUM
12th Maharashtra Board
IMPORTANT

Suppose error involved in making a certain measurement is continuous r.v. x  with p.d.f. fx=k4-x2, for -2x2 and =0 otherwise.
Compute PX>0

MEDIUM
12th Maharashtra Board
IMPORTANT

Suppose error involved in making a certain measurement is continuous r.v. x  with p.d.f. fx=k4-x2, for -2x2 and =0 otherwise.
Compute P-1<x<1

MEDIUM
12th Maharashtra Board
IMPORTANT

Suppose error involved in making a certain measurement is continuous r.v. x  with p.d.f. fx=k4-x2, for -2x2 and =0 otherwise.
Compute PX<0.5 or X>0.5

MEDIUM
12th Maharashtra Board
IMPORTANT

The p.d.f. of r.v. of X is given by fx=kx, for 0<x<4 and =0, otherwise. Determine k. Determine c.d.f. of X and hence PX2 and PX1.