Question

Arrange $\frac{3}{- 5}, \frac{- 7}{10}, \frac{- 11}{15}, \frac{- 13}{20}$ in ascending order.

Accepted Answer

We need to arrange $\frac{3}{- 5}, \frac{- 7}{10}, \frac{- 11}{15}, \frac{- 13}{20}$ in ascending order.

It can be written as $\frac{- 3}{5}, \frac{- 7}{10}, \frac{- 11}{15}, \frac{- 13}{20}$ .

The denominators of all the rational numbers are different.

Therefore, we will take LCM of the denominators.

LCM of $5, 10, 15$ and $20$ is $60$ .

$\Rightarrow \frac{- 3}{5} = \frac{- 3 \times 12}{5 \times 12} = \frac{- 36}{60}$

$\Rightarrow \frac{- 7}{10} = \frac{- 7 \times 6}{10 \times 6} = \frac{- 42}{60}$

$\Rightarrow \frac{- 11}{15} = \frac{- 11 \times 4}{15 \times 4} = \frac{- 44}{60}$

$\Rightarrow \frac{- 13}{20} = \frac{- 13 \times 3}{20 \times 3} = \frac{- 39}{60}$

Since the denominators are same, we can compare the numerators.

$\Rightarrow - 44 < - 42 < - 39 < - 36$

$\Rightarrow \frac{- 44}{60} < \frac{- 42}{60} < \frac{- 39}{60} < \frac{- 36}{60}$

Hence, $\frac{- 11}{15} < \frac{- 7}{10} < \frac{- 13}{20} < \frac{3}{- 5}$

R S Aggarwal Solutions for Chapter: Rational Numbers, Exercise 1: EXERCISE

R S Aggarwal Mathematics Solutions for Exercise - R S Aggarwal Solutions for Chapter: Rational Numbers, Exercise 1: EXERCISE

Questions from R S Aggarwal Solutions for Chapter: Rational Numbers, Exercise 1: EXERCISE with Hints & Solutions

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