For any two sets A and B , verify ( A ∪ B ) ' ∪ A ' ∩ B = A ' .

Let U = 1 , 2 , 3 , 4 , 5 , 6 , A = 1 , 2 and B = 4 , 5 Then, A ∪ B = 1 , 2 , 4 , 5 So, A ∪ B ' = U - A ∪ B = 1 , 2 , 3 , 4 , 5 , 6 - 1 , 2 , 4 , 5 = 3 , 6 Similarly, A ' = U - A = 1 , 2 , 3 , 4 , 5 , 6 - 1 , 2 = 3 , 4 , 5 , 6 Thus, A ' ∩ B = 3 , 4 , 5 , 6 ∩ 4 , 5 = 4 , 5 Then, ( A ∪ B ) ' ∪ A ' ∩ B = 3 , 6 ∩ 4 , 5 = 3 , 4 , 5 , 6 ∴ ( A ∪ B ) ' ∪ A ' ∩ B = A ' .

E M B I B E

Mathematics Standard 9>Chapter 1 - Set Language>Thinking Corner

Tamil Nadu Board Solutions for Chapter: Set Language, Exercise 18: Thinking Corner

Author:Tamil Nadu Board

Tamil Nadu Board Mathematics Solutions for Exercise - Tamil Nadu Board Solutions for Chapter: Set Language, Exercise 18: Thinking Corner

Attempt the free practice questions on Chapter 1: Set Language, Exercise 18: Thinking Corner with hints and solutions to strengthen your understanding. Mathematics Standard 9 solutions are prepared by Experienced Embibe Experts.