Use Heron's Formula to Find Area of Quadrilateral

A field is in the shape of a trapezium whose parallel sides are $25 \mathrm{m}$ and $10 \mathrm{m}$, and non-parallel sides are $14 \mathrm{m}$ and $13 \mathrm{m}$. Find the area of the field.

Each side of a rhombus shaped field is $30 \mathrm{m}$ and its longer diagonal is $48 \mathrm{m}$. Find the area of the field.

Find the area of the quadrilateral $\mathrm{ABCD}$ in which $\mathrm{AB}=6 \mathrm{cm}, \mathrm{BC}=4 \mathrm{cm}, \mathrm{CD}=3 \mathrm{cm}, \mathrm{DA}=5 \mathrm{cm}$ and $\angle \mathrm{C}=90°$

Find the area of the quadrilateral $\mathrm{ABCD}$ in which $\mathrm{AB}=3 \mathrm{cm}, \mathrm{BC}=4 \mathrm{cm}, \mathrm{CD}=5 \mathrm{cm}, \mathrm{DA}=4 \mathrm{cm}$ and $\angle \mathrm{B}=90°$

Find the area of the quadrilateral $\mathrm{ABCD}$ in which $\mathrm{AB}=6 \mathrm{cm}, \mathrm{BC}=4 \mathrm{cm}, \mathrm{CD}=4 \mathrm{cm}, \mathrm{DA}=5 \mathrm{cm}$ and $\mathrm{AC}=6 \mathrm{cm}$

Find the area of the quadrilateral $\mathrm{ABCD}$ in which $\mathrm{AB}=3.5 \mathrm{cm}, \mathrm{BC}=4.5 \mathrm{cm}, \mathrm{CD}=6 \mathrm{cm}, \mathrm{DA}=3 \mathrm{cm}$ and $\mathrm{BD}=5.5 \mathrm{cm}$

Find the area of the quadrilateral $\mathrm{ABCD}$ in which $\mathrm{AB}=3 \mathrm{cm}, \mathrm{BC}=5 \mathrm{cm}, \mathrm{CD}=6 \mathrm{cm}, \mathrm{DA}=6 \mathrm{cm}$ and $\mathrm{BD}=5 \mathrm{cm}$

Find the area of the quadrilateral $\mathrm{ABCD}$ in which $\mathrm{AB}=5 \mathrm{cm}, \mathrm{BC}=4.5 \mathrm{cm}, \mathrm{CD}=3.5 \mathrm{cm}, \mathrm{DA}=4 \mathrm{cm}$ and $\mathrm{AC}=6.5 \mathrm{cm}$