Michele Conway, Belle Cottingham, Alastair Duncombe and, Amanda George Solutions for Exercise 3: Exercise 1

Author:Michele Conway, Belle Cottingham, Alastair Duncombe & Amanda George

Michele Conway Mathematics Solutions for Exercise - Michele Conway, Belle Cottingham, Alastair Duncombe and, Amanda George Solutions for Exercise 3: Exercise 1

Attempt the free practice questions from Exercise 3: Exercise 1 with hints and solutions to strengthen your understanding. Cambridge Lower Secondary Maths Stage 9: Student's Book solutions are prepared by Experienced Embibe Experts.

Questions from Michele Conway, Belle Cottingham, Alastair Duncombe and, Amanda George Solutions for Exercise 3: Exercise 1 with Hints & Solutions

MEDIUM
Lower Secondary Stage 9
IMPORTANT

Use trial and improvement method to solve the equation to one decimal place.

xx+4=9

MEDIUM
Lower Secondary Stage 9
IMPORTANT

Use trial and improvement method to solve the equation to one decimal place.

5xx+2=19

MEDIUM
Lower Secondary Stage 9
IMPORTANT

Use trial and improvement method to solve the equation to one decimal place.

xx2+2=4

MEDIUM
Lower Secondary Stage 9
IMPORTANT

The table shows the values of x2-3x. Use the table to find a solution to each of the equation x2-3x=20. Give answer correct to 1 decimal place.

x x2-3x
6.1 18.9
6.2 19.8
6.3 20.8
6.4 21.8
6.5 22.8
6.6 23.8
6.7 24.8

MEDIUM
Lower Secondary Stage 9
IMPORTANT

The table shows the values of x2-3x. Use the table to find a solution to each of the equation x2-3x=22. Give answer correct to 1 decimal place.

x x2-3x
6.1 18.9
6.2 19.8
6.3 20.8
6.4 21.8
6.5 22.8
6.6 23.8
6.7 24.8

MEDIUM
Lower Secondary Stage 9
IMPORTANT

The table shows the values of x2-3x. Use the table to find a solution to each of the equation x2=3x+24. Give answer correct to 1 decimal place.

x x2-3x
6.1 18.9
6.2 19.8
6.3 20.8
6.4 21.8
6.5 22.8
6.6 23.8
6.7 24.8

MEDIUM
Lower Secondary Stage 9
IMPORTANT

John uses trial and improvement to solve the equation 3x2+2x=90 to 2 decimal places. He uses 5.3 as his starting point but the values seem to get further and further away from 90. Identify the mistake that John makes. Use trial and improvement to finds the correct answer.

Trial 3x2+2x Comment
x=5.3 3×5.32+2×5.3=94.87 Too big
x=5.4 3×5.42+2×5.4=98.28 Too big
x=5.5 3×5.52+2×5.5=101.75 Too big

MEDIUM
Lower Secondary Stage 9
IMPORTANT

The shaded area in the shape below is 100 cm2. Use trial and improvement to calculate the side length of the square to 1 decimal place.

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