NCERT Solutions for Chapter: Heron's Formula, Exercise 2: Exercise

The area of a $∆ABC$ is $8 {\mathrm{cm}}^2$ in which $AB=AC=4 \mathrm{cm}$ and $\angle A=90°$.

The area of the isosceles triangle is $\frac{5}{4}\sqrt{11} {\mathrm{cm}}^2$ if the perimeter is $11$ and the base is $5 \mathrm{cm}$.

The area of the equilateral triangle is $20\sqrt{3} {\mathrm{cm}}^2$ whose each side is $8 \mathrm{cm}$.

If the side of a rhombus is $10 \mathrm{cm}$ and one diagonal is $16 \mathrm{cm}$, then the area of the rhombus is $96 {\mathrm{cm}}^2$.

The base and the corresponding altitude of a parallelogram are $10 \mathrm{cm}$ and $3.5 \mathrm{cm}$ respectively. The area of the parallelogram is $30 {\mathrm{cm}}^2$.

The area of a regular hexagon of side $\text{'}a\text{'}$ is the sum of the areas of the five equilateral triangles with side $a$.

The cost of levelling the ground in the form of a triangle having the sides $51 \mathrm{m},37 \mathrm{m}\text{ and }20 \mathrm{m}$ at the rate of $₹3 \mathrm{per} {\mathrm{m}}^2 \mathrm{is} ₹918.$

In a triangle, the sides are given as $11 \mathrm{cm}, 12 \mathrm{cm} \text{and} 13 \mathrm{cm}$. The length of the altitude is approximately $10.25 \mathrm{cm}$ corresponding to the side having length $12 \mathrm{cm}$.