NCERT Solutions for Chapter: Kinetic Theory, Exercise 3: VSA

Author:NCERT

NCERT Physics Solutions for Exercise - NCERT Solutions for Chapter: Kinetic Theory, Exercise 3: VSA

Attempt the practice questions on Chapter 13: Kinetic Theory, Exercise 3: VSA with hints and solutions to strengthen your understanding. NCERT Exemplar Physics - Class 11 solutions are prepared by Experienced Embibe Experts.

Questions from NCERT Solutions for Chapter: Kinetic Theory, Exercise 3: VSA with Hints & Solutions

HARD
11th CBSE
IMPORTANT

Calculate the number of atoms in 39.4 gold. Molar mass of gold is 197 g mole-1

HARD
11th CBSE
IMPORTANT

The volume of a given mass of a gas at 27°C, 1 atm is 100 cc. What will be its volume at 327°C?

MEDIUM
11th CBSE
IMPORTANT

The molecules of a given mass of a gas have root mean square speeds of 100 m s-1  at 27°C and 1.00 atmospheric pressure. What will be the root mean square speeds of the molecules of the gas at 127° C and 2.0 atmospheric pressure?

MEDIUM
11th CBSE
IMPORTANT

Two molecules of a gas have speeds of 9×106 m s-1 and  1×106 m s-1 , respectively. What is the RMS speed of these molecules? 

MEDIUM
11th CBSE
IMPORTANT

A gas mixture consists of 2 moles of oxygen and 4 moles of neon at temperature T. Neglecting all vibrational modes, calculate the total internal energy of the system. (Oxygen has two rotational modes.)

MEDIUM
11th CBSE
IMPORTANT

Calculate the ratio of the mean free paths of the molecules of two gases having molecular diameters 1A and 2A. The gases may be considered under identical conditions of temperature, pressure and volume.