Given, 5 × _____ = 40 . Now, let us use the multiplication table of 5 to find the multiplicand. From the multiplication table of 5 , we get, 1 × 5 = 5 2 × 5 = 10 3 × 5 = 15 4 × 5 = 20 5 × 5 = 25 6 × 5 = 30 7 × 5 = 35 8 × 5 = 40 Hence, 5 × 8 = 40 . The required number is 8 .

' × ' imply multiplication Here, 54 is the product of the multiplication. Now, the number 54 can be written as product of 27 and 2 , 6 and 9 , 18 and 3 , 54 and 1 6 × 9 = 54 18 × 3 = 54 27 × 2 = 54 54 × 1 = 54 One of the above given combination of multiplicand and multiplier can be used to fill the given blanks.

Given, 5 × _____ = 35 . Now, let us use the multiplication table of 5 to find the multiplicand. From the multiplication table of 5 , we get, 1 × 5 = 5 2 × 5 = 10 3 × 5 = 15 4 × 5 = 20 5 × 5 = 25 6 × 5 = 30 7 × 5 = 35 8 × 5 = 40 Hence, 5 × 7 = 35 . The required number is 7 .

Given, _____ × 6 = 36 . Now, let us use the multiplication table of 6 to find the multiplicand. From the multiplication table of 6 , we get, 1 × 6 = 6 2 × 6 = 12 3 × 6 = 18 4 × 6 = 24 5 × 6 = 30 6 × 6 = 36 7 × 6 = 42 8 × 6 = 48 Hence, 6 × 6 = 36 . The required number is 6 .

' × ' imply multiplication. Multiplication can be defined as a form of repetitive addition. Multiplication of any number with 10 implies adding the number to itself ten times. Few examples are given below: 10 × 2 = 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 + 2 = 20 10 × 4 = 4 + 4 + 4 + 4 + 4 + 4 + 4 + 4 + 4 + 4 = 40 10 × 5 = 5 + 5 + 5 + 5 + 5 + 5 + 5 + 5 + 5 + 5 = 50 10 × 6 = 6 + 6 + 6 + 6 + 6 + 6 + 6 + 6 + 6 + 6 = 60 There are many more such examples and the blanks can be filled using any such example.

Given, _____ × 9 = 36 . Now, let us use the multiplication table of 9 to find the multiplicand. From the multiplication table of 9 , we get, 1 × 9 = 9 2 × 9 = 18 3 × 9 = 27 4 × 9 = 36 5 × 9 = 45 6 × 9 = 54 7 × 9 = 63 8 × 9 = 72 Hence, 4 × 9 = 36 . The required number is 4 .

Given, _____ × 7 = 28 . Now, let us use the multiplication table of 7 to find the multiplicand. From the multiplication table of 7 , we get, 1 × 7 = 7 2 × 7 = 14 3 × 7 = 21 4 × 7 = 28 5 × 7 = 35 6 × 7 = 42 7 × 7 = 49 8 × 7 = 56 Hence, 4 × 7 = 28 . The required number is 4 .

E M B I B E

MATH-MAGIC Book 3 Textbook in Mathematics for Class III>Chapter 9 - How Many Times?>Practice Time

NCERT Solutions for Chapter: How Many Times?, Exercise 9: Practice Time

Author:NCERT

NCERT Mathematics Solutions for Exercise - NCERT Solutions for Chapter: How Many Times?, Exercise 9: Practice Time

Attempt the free practice questions on Chapter 9: How Many Times?, Exercise 9: Practice Time with hints and solutions to strengthen your understanding. MATH-MAGIC Book 3 Textbook in Mathematics for Class III solutions are prepared by Experienced Embibe Experts.