Name: Understanding the Structure of Water
Uploaded: 2019-07-19
Duration: 2 min 13 s
Description: A water molecule contains two hydrogen atoms, each sharing a pair of electrons with an oxygen atom. The molecular shape is bent with an H-O-H angle of 104.5°...

Question

Correlate the items listed in Column I with those listed in Column II. Find out as many correlations as you can.

Column I		Column II
(i)	Synthesis gas	(a)	${Na}_{2} [{Na}_{4} {({PO}_{3})}_{6}]$
(ii)	Dihydrogen	(b)	Oxidizing agent
(iii)	Heavy water	(c)	Softening of water
(iv)	Calgon	(d)	Reducing agent
(v)	Hydrogen peroxide	(e)	Stoichiometric compounds of s-block elements
(vi)	Salt like hydrides	(f)	Prolonged electrolysis of water
		(g)	$Zn + NaOH$
		(h)	$Zn + dil . H_{2} {SO}_{4}$
		(i)	Synthesis of methanol
		(j)	Mixture of $CO$ and $H_{2}$

Accepted Answer

(i) Synthesis gas:

This synthesis gas is used for the production of methanol and many other hydrocarbons.

$CO (g) + 2 H_{2} (g) \to_{Catalyst}^{Cobalt} {CH}_{3} OH (l)$

(j) Synthesis gas is a mixture of $CO$ and $H_{2}$ , it is also known as syngas or water gas.

(ii)Dihydrogen:

Dihydrogen is a primary reducing agent.

The ionic or saline hydrides are the stoichiometric compounds of dihydrogen formed with s-block elements. Example: $NaH, KH$ etc.

Laboratory method of dihydrogen synthesis is by the reaction of zinc granules with an aqueous alkali solution.

$Zn + 2 NaOH \to \underset{Sodium zincate}{{Na}_{2} {ZnO}_{2}} + H_{2}$

Another laboratory method for synthesis of dihydrogen is by the reaction of zinc granules with dilute acid.

$Zn + 2 H^{+} \to {Zn}^{+ 2} + H_{2}$

Dihydrogen is used in the bulk synthesis of methanol.

$CO (g) + 2 H_{2} (g) \to_{Catalyst}^{Cobalt} {CH}_{3} OH (l)$

(iii) Heavy water

Heavy water can be prepared by the prolonged electrolysis of water.

(iv) Calgon:

${Na}_{2} [{Na}_{4} ({PO}_{3})_{6}]$ is known as Calgon.

It is used for softening of water, where the metal ion which causes hardness of water gets exchanged with sodium as follows:

${Na}_{6} P_{6} O_{18} \to 2 {Na}^{+} + {Na}_{4} P_{6} O_{18}^{2 -} M^{2 +} + {Na}_{4} P_{6} O_{18}^{2 -} \to {[{Na}_{2} {MP}_{6} O_{18}]}^{2 -} + 2 {Na}^{+} (M = Mg, Ca)$

(v) Hydrogen peroxide:

Hydrogen peroxide acts as oxidizing as well as reducing agents in both acidic and basic medium.

(vi) Salt like hydrides:

The ionic or saline hydrides are the stoichiometric compounds of dihydrogen formed with s-block elements. Example: $NaH, KH$ etc.

Column I Column II

(i) Synthesis gas
(i)

(j)

Synthesis of methanol

Mixture of $CO$ and $H_{2}$

(ii) Dihydrogen
(d)

(e)

(g)

(h)

(i)

Reducing agent

Stoichiometric compounds of s-block elements

$Zn + NaOH$

$Zn + dil . H_{2} {SO}_{4}$

Synthesis of methanol

(iii) Heavy water (f) Prolonged electrolysis of water

(iv) Calgon
(a)

(c)

${Na}_{2} [{Na}_{4} {({PO}_{3})}_{6}]$

Softening of water

(v) Hydrogen peroxide
(b)

(d)

Oxidizing agent

Reducing agent

(vi) Salt like hydrides (e) Stoichiometric compounds of s-block elements

Column I		Column II
(i)	Hydrogen peroxide is used as a	(a)	zeolite
(ii)	Used in Calgon method	(b)	perhydrol
(iii)	Permanent hardness of hard water is removed by	(c)	sodium hexametaphosphate
		(d)	propellant

NCERT Solutions for Chapter: Hydrogen, Exercise 1: Matching Type

NCERT Chemistry Solutions for Exercise - NCERT Solutions for Chapter: Hydrogen, Exercise 1: Matching Type

Questions from NCERT Solutions for Chapter: Hydrogen, Exercise 1: Matching Type with Hints & Solutions

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Column I		Column II
(i)	$H$	(a)	Used in the name of perhydrol.
(ii)	$H_{2}$	(b)	Can be reduced to dihydrogen by $NaH$ .
(iii)	$H_{2} O$	(c)	Can be used in hydroformylation of olefin.
(iv)	$H_{2} O_{2}$	(d)	Can be used in cutting and welding.

Column I		Column II
(i)	Electrolysis of water produces	(a)	atomic reactor
(ii)	Lithium aluminium hydride is used as	(b)	polar molecule
(iii)	Hydrogen chloride is a	(c)	recombines on the metal surface to generate high temperature
(iv)	Heavy water is used in	(d)	reducing agent
(v)	Atomic hydrogen	(e)	hydrogen and oxygen