NCERT Solutions for Chapter: Thermodynamics, Exercise 1: Short Answer Type

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NCERT Chemistry Solutions for Exercise - NCERT Solutions for Chapter: Thermodynamics, Exercise 1: Short Answer Type

Attempt the practice questions on Chapter 6: Thermodynamics, Exercise 1: Short Answer Type with hints and solutions to strengthen your understanding. NCERT Exemplar Chemistry - Class 11 solutions are prepared by Experienced Embibe Experts.

Questions from NCERT Solutions for Chapter: Thermodynamics, Exercise 1: Short Answer Type with Hints & Solutions

MEDIUM
11th CBSE
IMPORTANT

The enthalpy of vapourisation of CCl4 is 30.5 kJ mol-1. Calculate the heat required for the vapourisation of 284 g of CCl4 at constant pressure. (Molar mass of CCl4= 154 g mol-1).
 

MEDIUM
11th CBSE
IMPORTANT

The enthalpy of reaction for the reaction:

2H2(g) + O2(g)  2H2O(l) is rH= 572 kJ mol-1. What will be standard enthalpy of formation of H2O (l)?  

MEDIUM
11th CBSE
IMPORTANT

What will be the work done on an ideal gas enclosed in a cylinder, when it is compressed by a constant external pressure, pext in a single step as shown in Figure? Explain graphically.

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MEDIUM
11th CBSE
IMPORTANT

How will you calculate work done on an ideal gas in a compression, when change in pressure is carried out in infinite steps?

HARD
11th CBSE
IMPORTANT

Represent the potential energy/enthalpy change in the following processes graphically.

(a) Throwing a stone from the ground to roof. 

(b) 12H2g+ 12 Cl2g HClg         rH=92.32 kJ mol-1

In which of the processes potential energy/enthalpy change is contributing factor to the spontaneity?
 

MEDIUM
11th CBSE
IMPORTANT

Enthalpy diagram for a particular reaction is given in Figure. Is it possible to decide spontaneity of a reaction from given diagram? Explain.

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MEDIUM
11th CBSE
IMPORTANT

1.0 mol of a monoatomic ideal gas is expanded from state (1) to state (2) as shown in Figure. Calculate the work done for the expansion of gas from state (1) to state (2) at 298 K.

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MEDIUM
11th CBSE
IMPORTANT

An ideal gas is allowed to expand against a constant pressure of 2 bar from 10 L to 50 L in one step. Calculate the amount of work done by the gas. If the same expansion were carried out reversibly, will the work done be higher or lower than the earlier case? (Given that 1 L  bar = 100 J)