NCERT Solutions for Chapter: Number Systems, Exercise 1: Exercise

After rationalising the denominator of $\frac{7}{3\sqrt{3}-2\sqrt{2}},$ we get the denominator as

The value of $\frac{\sqrt{32}+\sqrt{48}}{\sqrt{8}+\sqrt{12}}$ is equal to

If $\sqrt{2}=1.4142$, then $\sqrt{\frac{\sqrt{2}-1}{\sqrt{2}+1}}$ is equal to

$\sqrt[4]{\sqrt[3]{2^2}}$equals

The product $\sqrt[3]{2}·\sqrt[4]{2}·\sqrt[12]{32}$equals

Value of $\sqrt[4]{(81{)}^{-2}}$ is

Value of $(256{)}^{0.16}\times (256{)}^{0.09}$ is

Which of the following is equal to $x$?