Vernier Callipers

A screw gauge having $100$ equal circular divisions and a pitch of length $1 \mathrm{mm}$ is used to measure the diameter of a wire of length $5.6 \mathrm{cm}.$ The main scale reading is $1 \mathrm{mm}$ and the ${47}^{\mathrm{th}}$ circular division coincides with the main scale. Find the diameter of the wire.

The side of a cube is measured by Vernier calipers ($10$ divisions of the vernier scale coincide with$9$divisions of the main scale, where $1$ division of main scale is $1 \mathrm{mm}$). The main scale reads $10 \mathrm{mm}$ and the first division of vernier scale coincides with the main scale. The mass of the cube is $2.736 \mathrm{g}.$ Find the density of the cube in appropriate significant figures.

Consider the following data: $10\mathrm{MSDs}=1 \mathrm{cm}, 10\mathrm{VSD}s=9\mathrm{MSDs}$. Zero of Vernier scale is to the right of the zero marking of the main scale with $6 \mathrm{VSDs}$ coinciding with MSDs and the actual reading for length measurement is $4.3 \mathrm{cm}$ with $2\mathrm{VSDs}$ coinciding with main scale graduations. Estimate the length.

The vernier scale of a travelling microscope has $50$ divisions which coincide with $49$ main scale divisions. If each main scale division is $0.5 \mathrm{mm}$, calculate the minimum inaccuracy in the measurement of distance.

$1 \mathrm{cm}$ on the main scale of vernier calipers is divided into $10$ equal parts. If $20$ divisions of vernier scale coincide with $10$ small divisions of the main scale, what will be the least count of calipers?

There are two Vernier calipers both of which have $1 \mathrm{cm}$ divided into $10$ equal divisions on the main scale. The Vernier scale of one of the calipers $\left(C_1\right)$ has $10$ equal divisions that correspond to $9$ main scale divisions. The Vernier scale of the other caliper $\left(C_2\right)$ has $10$ equal divisions that correspond to $11$ main scale divisions. The readings of the two calipers are shown in the figure. The measured values (in $\mathrm{cm}$) by calipers $C_1$ and $C_2$ respectively, are

The diameter of a cylinder is measured using Vernier calipers with no zero error. It is found that the zero of the Vernier scale lies between $5.10 \mathrm{cm}$ and $5.15 \mathrm{cm}$ of the main scale. The Vernier scale has $50$ divisions equivalent to $2.45 \mathrm{cm}$. The $24\mathrm{th}$ division of the Vernier scale exactly coincides with one of the main scale divisions. The diameter of the cylinder is

A vernier calipers has $1 \mathrm{mm}$ marks on the main scale. It has $20$ equal divisions on the vernier scale which match with $16$ main scale divisions. For this vernier calipers, the least count is,

In an experiment, the angles are required to be measured using an instrument. $29$ divisions of the main scale exactly coincide with $30$ divisions of the vernier scale. If the smallest division of the main scale is half-a-degree $\left(=0.5°\right),$ then the least count of the instrument is

The main scale of a vernier calipers reads in $\mathrm{milimeter}$ and its vernier is divided into $10$ divisions which coincides with $9$ divisions of the main scale. Find the reading for shown situation in $\mathrm{mm}$.

If $S$ and $V$ are one main scale and one Vernier scale divisions and $n-1$ divisions on the main scale are equivalent to $n$ divisions of the Vernier, then:
 

The internal and external diameters of a hollow cylinder are measured with the help of a Vernier calipers. Their values are $4.23 \pm 0.01 \mathrm{cm}$ and $3.87 \pm 0.01 \mathrm{cm},$ respectively. The thickness of the wall of the cylinder is

The effective length of a simple pendulum is the sum of the following three: length of string, radius of bob, and length of hook. In a simple pendulum experiment, the length of the string, as measured by a meter scale, is $92.0 \mathrm{cm}$. The radius of the bob combined with the length of the hook, as measured by a vernier callipers, is $2.15 \mathrm{cm}$. The effective length of the pendulum is