Bernoulli’s Theorem and Its Applications

Bernoulli's theorem is based on the principle of conservation of

A cylindrical tank with a large diameter is filled with water. Water drains out through a hole at a bottom of the tank. If the cross-sectional area of the hole is $6 {\mathrm{cm}}^2$ then the drainage rate $\left({\mathrm{m}}^3 {\mathrm{s}}^{-1}\right)$ when the depth of the water is $0.2 \mathrm{m}$, is

The pressure of water in a water pipe when tap is opened and closed is respectively $3 \times {10}^5 \mathrm{N}/{\mathrm{m}}^2$ and $3.5 \times {10}^5 \mathrm{N}/{\mathrm{m}}^2$.With open tap the velocity of water flowing is:

An application of Bernoulli's equation for fluid flow is found in

Paint-gun is based on,

A fluid is flowing through a horizontal pipe of varying cross-section, with $\mathrm{v}{\mathrm{ms}}^{-1}$ at a point where the pressure is $\mathrm{P}$ Pascal. At another point where pressure $\frac{\mathrm{P}}{2}$ Pascal its speed is $\mathrm{V} {\mathrm{ms}}^{-1}$. If the density of the fluid is $\mathrm{\rho }\mathrm{kg}-{\mathrm{m}}^{-3}$ and the flow is streamline, then $\mathrm{V}$ is equal to 

There is a hole in the bottom of tank having water. If total pressure at the bottom is $3 \mathrm{atm}$ $\left(1 \mathrm{atm}={10}^5 \mathrm{N} {\mathrm{m}}^{-2}\right)$, then, the velocity of water flowing from hole is

A manometer connected to a closed tap reads $4.5\times {10}^5$ pascal. When tap is opened the reading of manometer falls to $4\times {10}^5$ pascal. The velocity of flow is

Sudden fall of atmospheric pressure by a large amount indicates$\_\_\_\_\_\_\_\_ .$

Air is streaming past a horizontal air-plane wing such that its speed in $120 \mathrm{m} {\mathrm{s}}^{-1}$ over the upper surface and $90 \mathrm{m} {\mathrm{s}}^{-1}$ at the lower surface. If the density of air is $1.3 \mathrm{kg} {\mathrm{m}}^{-3}$ and the wing is $10 \mathrm{m}$ long and has an average width of $2 \mathrm{m}$, then the difference of the pressure on the two sides of the wing is

A cylinder of height $20 \mathrm{m}$ is completely filled with water. The velocity (in $\mathrm{m} {\mathrm{s}}^{-1}$) of efflux of water through a small hole on the side of cylinder near bottom is

Bernoulli's principle is based on the principle of

A plane is in level flight at constant speed and each of its two wings has an area of $20 {\mathrm{m}}^2$. If the speed of the air is $180 \mathrm{km} {\mathrm{h}}^{-1}$ over the lower wing and $216 \mathrm{km} {\mathrm{h}}^{-1}$ over the upper wing surface, determine the plane's mass. (Take air density to be $1 {\mathrm{kgm}}^{-3}$ and $\mathrm{g}=10 \mathrm{m} {\mathrm{s}}^{-2}$).

A tank of height $5 \mathrm{m}$ is full of water. There is a hole of cross-sectional area $1 {\mathrm{cm}}^2$ in its bottom. The initial volume of water that will come out from this hole per second is: 

Water flows through a frictionless duct with a cross-section varying as shown in figure. Pressure P at points along the axis is represented by: 

Water from a tap emerges vertically downwards with an initial speed of 1.0 m/s. The cross-sectional area of tap is 10^–4 m². Assume that the pressure is constant throughout the stream of water and that the flow is steady, the cross-sectional area of stream 0.15 m below the tap is :-

The velocity of the liquid coming out of a small hole of a large vessel containing two different liquids of densities $2\rho$ and $\rho$as shown in the figure is

A cylindrical container of radius$R$ and height $h$ is completely filled with a liquid. Two horizontal $L$ shaped pipes of a small cross-section area $a$ are connected to the cylinder as shown in the figure. Now the two pipes are opened and fluid starts coming out of the pipes horizontally in opposite directions. Then the torque due to ejected liquid on the system is:

Water is flowing through a long horizontal tube. Let $P_{\mathrm{A}}$ and $P_{\mathrm{B}}$ be the pressures at two points $\mathrm{A}$ and $\mathrm{B}$ of the tube. Which of the following is true?

There is a hole in the bottom of a tank having water. If the total pressure at the bottom is $3$ $\mathrm{atm}$ ($1 \mathrm{atm}={10}^5 \mathrm{N} {\mathrm{m}}^{-2}$), then, the velocity of water flowing from the hole is