Escape Velocity

If a projectile has a velocity greater than the escape velocity, which trajectory will it follow?

A space station is at a height equal to the radius of the Earth. If '$V_E$' is the escape velocity on the surface of the Earth, the same on the space station is _____$V_E$.

A body is projected vertically upwards from earth's surface with velocity $2v_e,$ where $v_{\mathit{e}}$ is escape velocity from earth's surface. The velocity when body escapes the gravitational pull is

If the moon is to escape from the gravitational field of the earth forever, it will require a velocity ___ .

Escape velocity when a body of mass $m$ is thrown vertically from the surface of the earth is $v\text{,}$ what will be the escape velocity of another body of mass $4 \mathrm{m}$ is thrown vertically

The escape velocity of a body on an imaginary planet which is thrice the radius of the earth and double the mass of the earth is (${\mathrm{v}}_{\mathrm{e}}$ is the escape velocity of earth)

Two planets have masses $\mathrm{M}$ and $16 \mathrm{M}$ and their radii are a and $2\mathrm{a}$, respectively. The separation between the centres of the planets is $10\mathrm{a}$. A body of mass $\mathrm{m}$ is fired from the surface of the larger planet towards the smaller planet along the line joining their centres. For the body to be able to reach at the surface of smaller planet, the minimum firing speed needed is :

Acceleration due to gravity on a planet is $10$ times the value on the Earth. Escape velocity for the planet and the Earth are $v_{\mathrm{P}}$ and $v_{\mathrm{e}}$, respectively. Assuming that the radii of the planet and the Earth are same, then

For a satellite, escape velocity is $11 \mathrm{km} {\mathrm{s}}^{-1}$. If the satellite is launched at an angle of $60°$ with the vertical, then escape velocity will be

Potential energy of a $3 \mathrm{kg}$ body at the surface of a planet is $-54 \mathrm{J}$, then escape velocity will be

The ratio of radii of two planets is $p$ and the ratio of accelerations due to gravity at their surfaces is $q$. The ratio of escape velocities from their surfaces will be

The escape velocity is $11 \mathrm{km} {\mathrm{s}}^{-1}$ at the surface of the earth. If the planet has a radius twice that of the earth and density equal to that of the earth, then the escape velocity at the surface of the planet is

Escape velocity from the earth's surface is $11.2 \mathrm{km} {\mathrm{s}}^{-1}$. Another planet of the same mass has radius $\frac{1}{4}$ times that of the earth. What is the escape velocity from the surface of the planet?

Escape velocity on a planet is $v_{\mathrm{e}}$. If the radius of the planet remains the same and its mass becomes $4$ times, the escape velocity becomes

Find the maximum height achieved by a rocket launched from earth's surface with half of the velocity required to just escape the earth's orbit. (Take the earth's radius to be $R$.)

If a missile is launched with a velocity less than the escape velocity, the sign of its total energy is

Planet $A$ has mass $M$ and radius $R.$ Planet $B$ has half the mass and half the radius of Planet $A.$ If the escape velocities from the Planets $A$ and $B$ are $v_A$ and $v_B,$ respectively, then $\frac{v_A}{v_B}=\frac{n}{4}.$ The value of $n$ is:

The escape speed of a body on the earth's surface is $11.2\mathrm{ }\mathrm{k}\mathrm{m}\mathrm{ }{\mathrm{s}}^{-1}$. A body is projected with thrice of this speed. The speed of the body when it escapes the gravitational pull of earth is

A satellite is moving with a constant speed $v$ in circular orbit around the earth. An object of mass 'm' is ejected from the satellite such that it just escapes from the gravitational pull of the earth. At the time of ejection, the kinetic energy of the object is:

If the escape speed of a projectile on Earth's surface is $11.2 \mathrm{km} {\mathrm{s}}^{-2}$ and a body is projected out with thrice this speed, then determine the speed of the body far away from the Earth