Capillary Rise

A long capillary tube of mass $\text{'}\pi \text{'}$ $\mathrm{g},$ radius $2 \mathrm{mm}$ and negligible thickness, is partially immersed in a liquid of surface tension $0.1 \mathrm{N}/\mathrm{m}.$ Take angle of contact zero and neglect the buoyant force of liquid. The force required to hold the tube vertically is $\frac{3\pi }{2500}x$ newton. Find $x.\left(g=10 \mathrm{m}/{\mathrm{s}}^2\right)$

A capillary tube of radius $r$ is immersed in water and water rises in it to a height $h$. The mass of water in the capillary tube is $5\mathrm{g}$. Another capillary tube of radius $2r$ is immersed in water. The mass of water that will rise in this tube is 

Three liquids of densities ${\rho }_1, {\rho }_2$ and ${\rho }_3$ (with $\left.{\rho }_1>{\rho }_2>{\rho }_3\right),$ having the same value of surface tension T, rise to the same height in three identical capillaries. The angles of contact ${\theta }_1$ ${\theta }_2$ and ${\theta }_3$ obey 

In a capillary tube having area of cross-section $"A"$, water rises to a height $\text{'}h\text{'}$. If cross sectional area is reduced to $\frac{\text{'}A\text{'}}{9},$ the rise of water in the capillary tube is