Embibe Experts Solutions for Chapter: Work, Energy and Power, Exercise 2: Level 2

Adjacent figure shows the force-displacement graph of a moving body, the work done in displacing body from $x=0$ to $x=35 \mathrm{m}$ is equal to

A particle with total mechanical energy which is small and negative is under the influence of a one dimensional potential $U\left(x\right)=\frac{x^4}{4}-\frac{x^2}{2} \mathrm{J}$, where $x$ is in meters. At time $t=0 \mathrm{s},$ it is at $x=-0.5 \mathrm{m}.$ Then at a later time it can be found,

A block of mass $5 \mathrm{kg}$ is released from rest when compression in spring is $2 \mathrm{m}$. Block is not attached with the spring and natural length of the spring is $4 \mathrm{m}$. Maximum height of block from ground is$\left(g=10 \mathrm{m} {\mathrm{s}}^{-2}\right)$

A particle of mass $m_1$ moves with speed $u_1$ and collide head on with a stationary particle of mass $m_2.$ After the collision, the velocities of the particles are $v_1$ and $v_2,$ and $e$ is coefficient of restitution for the collision. If $v_1$ is to be positive, i.e. for the first particle to continue moving in same direction then:

During the head-on collision of two masses $1 \mathrm{kg}$ and $2 \mathrm{kg}$ the maximum energy of deformation is $\frac{100}{3} \mathrm{J}\text{.}$ If before the collision the masses are moving in the same direction, then their velocity of the approach before the collision is

In the figure shown, coefficient of restitution between $A$ and $B$ is $e=\frac{1}{2},$ then

A ball $A$ of mass $M$ collides elastically with another identical ball $B$ at rest as shown in the figure. Initially, velocity of the ball $A$ is $u \mathrm{m} {\mathrm{s}}^{-1}\text{.}$ After collision

In the figure given below, the mass on the left is moving to the right with a constant velocity $v$ and after colliding inelastically with the mass on the right, sticks to it. If the spring of spring constant $k$ was initially at its equilibrium position, what is the amplitude to the resultant oscillation?