Current Carrying Loop as a Magnetic Dipole

A ring of radius $\mathrm{R}$ with charge $\mathrm{q}$ uniformly distributed over it is rotated with angular speed $\mathrm{\omega }$ around its axis. Find magnetic moment of the ring.

An insulating rod of length $l$ carries a charge $q$, distributed uniformly on it. The rod is pivoted at its mid point and is rotated at a frequency $f$ about a fixed axis perpendicular to rod and passing through the pivot. The magnetic moment of the rod system is

The magnetic moment of an electron orbiting in a circular orbit of radius $r$ with a speed $v$ is equal to

A straight wire carrying current $I$ is turned into a circular loop. If the magnitude of the magnetic moment associated with it is $M$, then the length of the wire will be

Relation between magnetic moment and angular velocity is:-

A charge $q$ is spread uniformly over an isolated ring of radius $R$. The ring is rotated about its natural axis and has a magnetic dipole moment of the ring as $M$. Angular velocity of rotation is

A current carrying coil behave like tiny magnet. If area of coil is A and magnetic moment is ‘M’ then current through the coil is :-

A circular loop has a radius of 5 cm. and it is carrying a current of 0.1 A. its magnetic moment is :

Find the magnetic moment of a thin round loop with current if the radius of the loop is equal to $r$ and the magnetic induction at its centre is equal to $X$.

A circular coil of diameter $9 \mathrm{cm}$ has $30$ turns of wire which carry current of $1$ ampere. The magnetic moment of the coil is

A circular coil of radius $10 \mathrm{cm}$ and $100 \mathrm{turns}$ carries a current $1 \mathrm{A}$. What is the magnetic moment of the coil?
 

A coil carrying current $I$ has radius $r$ and number of turns $n$. It is rewound so that radius of new coil is $\frac{r}{4}$ and it carries current 'I'. The ratio of magnetic moment of new coil to that of original coil is 
 

A steel wire of length ${}^{\text{'}}l^{\text{'}}$ has a magnetic moment $M$. It is bent in $L$ shape having equal size of arm. The new magnetic moment is
 

A current of $10 \mathrm{A}$ is flowing through a circular coil of $5 \mathrm{turns}$, each of radius $7 \mathrm{cm}$. The coil lies in the $\mathrm{X}-\mathrm{Y}$ plane. What is the magnitude and direction of the magnetic dipole moment associated with it?
 

The magnetic dipole moment of the earth is $6.4\times {10}^{21}\mathrm{A} {\mathrm{m}}^2$ . If we assume it to be due to a current loop wound around the magnetic equator of the earth, then what should be the magnitude of the current, if the equatorial radius is $6.4\times {10}^6 \mathrm{m}?$
 

Magnetic dipole moment of a current-carrying coil is independent of
 

A steady current $l$ flows in a small square loop of wire of side $L$ in a horizontal plane. The loop is now folded about its middle such that half of it lies in a vertical plane. Let $\overrightarrow{{\mathrm{\mu }}_1}$ and $\overrightarrow{{\mathrm{\mu }}_2}$, respectively denote the magnetic moments of the current loop before and after folding. Then

A circular loop and a square loop are formed from two wires of the same length and cross-section. The same current is passed through them. Then the ratio of their dipole moments is

A wire of length $l$, carrying current $i$, is bent in circle of radius $r$, then magnetic moment at centre of loop is

A coil of length $L,$ carries a current $i$. The magnetic moment of coil is proportional to