Embibe Experts Solutions for Chapter: Wave Optics, Exercise 3: Level 3

Two points separated by a distance of $0.1 \mathrm{mm}$ can just be resolved in a microscope when a light of wavelength $6000 Å$ is used. If the light of wavelength $4800 Å$ is used this limit of resolution becomes

Two tree are at distance of $3.14 \mathrm{m}$ from each other. What should the maximum distance of an observer from tree to see them separately

Two point white dots are $1 \mathrm{mm}$ apart on a black paper. They are viewed by eye of pupil diameter $3 \mathrm{mm}$. Approximately, what is the maximum distance at which these dots can be resolved by the eye :-

(Take wavelength of light $=500 \mathrm{nm}$ )

In a given direction, the intensities of the scattered light by scattering substance for two beams of light are in the ratio of $256 : 81.$ The ratio of the frequency of the first beam to the frequency of the second because

Which of the following statement is not true for interference and diffraction?

The direction of the first secondary maximum in the Fraunhofer diffraction pattern at a single slit is given by ($a$ is the width of the slit and $\theta$ is the angular position):

Light of wavelength $6328 \mathrm{\AA }$ is incident normally on slit having a width of $0.2 \mathrm{mm}$. The width of the central maximum measured from minimum to minimum of diffraction pattern on a screen $9.0$ meters away will be about-

A slit of width $d$ is illuminated by a parallel beam of light of wavelength $500 \mathrm{nm}$ and diffraction pattern is observed on a screen kept at a distance of $1 \mathrm{m}$.  It is observed that the first minima is at a distance of $2.5 \mathrm{mm}$  from the centre of the screen. Find the value of $d$.