David Sang and Graham Jones Solutions for Chapter: Forces: Vectors and Moments, Exercise 2: Questions

A parachutist weighs $1000 \mathrm{N}$. When she opens her parachute, it pulls upwards on her with a force of $2000 \mathrm{N}$

Draw a diagram to show the forces acting on the parachutist.

A parachutist weighs $1000 \mathrm{N}$. When she opens her parachute, it pulls upwards on her with a force of $2000 \mathrm{N}$

Calculate the resultant force acting on her.

A parachutist weighs $1000 \mathrm{N}$. When she opens her parachute, it pulls upwards on her with a force of $2000 \mathrm{N}$

What effect will this force have on her?

The ship shown in Figure is travelling at a constant velocity.

Is the ship in equilibrium (in other words, is the resultant force on the ship equal to zero)? How do you know?

The force $\mathrm{D}$ is the frictional drag of the water on the boat. Like air resistance, drag is always in the opposite direction to the object's motion.

The ship shown in Figure is travelling at a constant velocity.

What is the upthrust $\mathrm{U}$ Of the water?

The force $\mathrm{D}$Is the frictional drag of the water on the boat. Like air resistance, drag is always in the opposite direction to the object's motion.

The ship shown in Figure is travelling at a constant velocity.

What is the drag $\mathrm{D}$ of the water?

The force $\mathrm{D}$ is the frictional drag of the water on the boat. Like air resistance, drag is always in the opposite direction to the object's motion.

A stone is dropped into a fast-flowing stream. It does not fall vertically because of the sideways push of the water. Calculate the resultant force on the stone.

A stone is dropped into a fast-flowing stream. It does not fall vertically because of the sideways push of the water

Is the stone in equilibrium?