Simplify 3 2 3 × 2 1 3

Given, 3 2 3 × 2 1 3 Convert the mixed fractions into improper fractions. 11 3 × 7 3 When multiplying two fractions multiply the numerators (the top numbers) together, and then multiply the denominators (the bottom numbers) together. So, 11 × 7 3 × 3 = 77 9 = 8 5 9 Thus, the required answer is 8 5 9 .

Simplify 4 4 5 × 2 2 3

Given, 4 4 5 × 2 2 3 Convert the mixed fractions into improper fractions. 24 5 × 8 3 When multiplying two fractions multiply the numerators (the top numbers) together, and then multiply the denominators (the bottom numbers) together. So, 24 × 8 5 × 3 = 192 15 = 64 5 = 12 4 5 Thus, the required answer is 12 4 5 .

Simplify 3 1 2 × 5 14 × 4 3 10

Given, 3 1 2 × 5 14 × 4 3 10 Convert the mixed fractions into improper fractions. 7 2 × 5 14 × 43 10 When multiplying two or more fractions multiply the numerators (the top numbers) together, and then multiply the denominators (the bottom numbers) together. So, 7 × 5 × 43 2 × 14 × 10 = 1505 280 = 43 8 = 5 3 8 Thus, the required answer is 5 3 8 .

Simplify 11 1 2 × 1 1 23 × 7 1 5

Given, 11 1 2 × 1 1 23 × 7 1 5 Convert the mixed fractions into improper fractions. 23 2 × 24 23 × 36 5 When multiplying two fractions multiply the numerators (the top numbers) together, and then multiply the denominators (the bottom numbers) together. So, 23 × 24 × 36 2 × 23 × 5 = 24 × 36 2 × 5 = 24 × 18 5 = 432 5 = 86 2 5 Thus, the required answer is 86 2 5 .

Simplify 2 5 × 3 1 5 × 2 1 3

Given, 2 5 × 3 1 5 × 2 1 3 Convert the mixed fractions into improper fractions. 2 5 × 16 5 × 7 3 When multiplying two fractions multiply the numerators (the top numbers) together, and then multiply the denominators (the bottom numbers) together. So, 2 × 16 × 7 5 × 5 × 3 = 224 75 = 2 74 75 Thus, the required answer is 2 74 75 .

Simplify 2 3 10 × 3 1 2 × 4 7 10

Given, 2 3 10 × 3 1 2 × 4 7 10 Convert the mixed fractions into improper fractions. 23 10 × 7 2 × 47 10 When multiplying two or more fractions multiply the numerators (the top numbers) together, and then multiply the denominators (the bottom numbers) together. So, 23 × 7 × 47 10 × 2 × 10 = 7567 200 = 37 167 200 Thus, the required answer is 37 167 200 .

E M B I B E

Cambridge connection Mathematics>Chapter 2 - Fractions>Let's Practice

Prakash Tiwari and Ishita Joshi Solutions for Chapter: Fractions, Exercise 3: Let's Practice

Author:Prakash Tiwari & Ishita Joshi

Prakash Tiwari Mathematics Solutions for Exercise - Prakash Tiwari and Ishita Joshi Solutions for Chapter: Fractions, Exercise 3: Let's Practice

Attempt the free practice questions on Chapter 2: Fractions, Exercise 3: Let's Practice with hints and solutions to strengthen your understanding. Cambridge connection Mathematics solutions are prepared by Experienced Embibe Experts.