In Δ ABC , ∠ B = 90 ° , AB = y units, BC = 3 units, A C = 2 units and angle A = x ° , find sin x °

Given, in ∆ A B C , Δ ABC , ∠ B = 90 ° , AB = y units, BC = 3 units, A C = 2 units and angle A = x ° To find: sin x ° We know that the sine of an angle of a right-angled triangle is the ratio of its perpendicular (that is side opposite to the angle) to the hypotenuse. Thus, from the given figure, we have sin x ° = B C A C = 3 2 Hence, sin x ° = 3 2

In Δ ABC , ∠ B = 90 ° , AB = y units, BC = 3 units, A C = 2 units and angle A = x ° , find x °

Given, in ∆ A B C , Δ ABC , ∠ B = 90 ° , AB = y units, BC = 3 units, A C = 2 units and angle A = x ° To find: x ° We know that the sine of an angle of a right-angled triangle is the ratio of its perpendicular (that is side opposite to the angle) to the hypotenuse. Thus, from the given figure, we have sin x ° = B C A C = 3 2 ⇒ sin x ° = sin 60 ° ∵ sin 60 ° = 3 2 Hence, x ° = 60 °

In Δ ABC , ∠ B = 90 ° , AB = y units, BC = 3 units, A C = 2 units and angle A = x ° , find tan x °

Given, in ∆ A B C , Δ ABC , ∠ B = 90 ° , AB = y units, BC = 3 units, A C = 2 units and angle A = x ° To find: x ° We know that the sine of an angle of a right-angled triangle is the ratio of its perpendicular (that is side opposite to the angle) to the hypotenuse. Thus, from the given figure, we have sin x ° = B C A C = 3 2 ⇒ sin x ° = sin 60 ° ∵ sin 60 ° = 3 2 ⇒ x ° = 60 ° Now, tan x ° = tan 60 ° = 3 Hence, the required value is 3 .

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Concise Mathematics I.C.S.E - Class IX>Trigonometry>Chapter 23 - Trigonometrical Ratios of Standard Angles [Including Evaluation of an Expression Involving Trigonometric Ratios]>EXERCISE

R K Bansal Solutions for Exercise 1: EXERCISE

Author:R K Bansal

R K Bansal Mathematics Solutions for Exercise - R K Bansal Solutions for Exercise 1: EXERCISE

Attempt the practice questions from Exercise 1: EXERCISE with hints and solutions to strengthen your understanding. Concise Mathematics I.C.S.E - Class IX solutions are prepared by Experienced Embibe Experts.