3 2 13 = 3 × 13 + _ _ _ _ _ 13 = _ _ _ _ _ .

Given that, The given fraction is 3 2 13 = 3 × 13 + 13 . A fraction is represented with its quotient and the remainder is a mixed fraction. In this fraction, the three value is multiplied with denominator the and added the denominator result with the numerator. 3 2 13 = 39 + 2 13 = 41 13 So, the simplified value is 41 13 . Hence, 3 2 13 = 13 × 3 + 2 13 = 41 13 .

- 4 3 5 = _ _ _ _ _ = _ _ _ _ _ .

Given that, The given fraction is - 4 3 5 . We know that, A fraction is represented with its quotient and the remainder is a mixed fraction. In this given fraction for is multiplied with the denominator, and the result of that denominator is added by the numerator. - 4 3 5 = - 4 × 5 + 3 5 = - 23 5 The value of a given fraction is = - 23 5 . Hence, - 4 3 5 = - 4 × 5 + 3 5 = - 23 5

E M B I B E

Concise Mathematics Middle School Class 6>Chapter 14 - Fractions>EXERCISE

R K Bansal Solutions for Chapter: Fractions, Exercise 1: EXERCISE

Author:R K Bansal

R K Bansal Mathematics Solutions for Exercise - R K Bansal Solutions for Chapter: Fractions, Exercise 1: EXERCISE

Attempt the free practice questions on Chapter 14: Fractions, Exercise 1: EXERCISE with hints and solutions to strengthen your understanding. Concise Mathematics Middle School Class 6 solutions are prepared by Experienced Embibe Experts.