5 - 10 = _____, which is not a _____ ⇒ Subtraction of _____ is not closed.

Given that, 5 - 10 = _____, which is not a _____ ⇒ Subtraction of _____ is not closed. ⇒ 5 - 10 = - 5 The natural numbers along with ' 0 ' (zero) form a collection of whole numbers. Here, 5 - 10 is not a whole number. If x and y are two whole numbers, then x - y is not necessarily a whole number. So, the Subtraction of whole numbers is not closed. Therefore, 5 - 10 = - 5 , which is not a whole number. ⇒ Subtraction of whole numbers is not closed.

7 - 18 = _____ and 7 - 18 - 5 = _____ 7 - 18 - 5 18 - 5 = _____ and 7 - 18 - 5 = _____ Is 7 - 18 - 5 = 7 - 18 - 5 ? ⇒ Subtraction of whole numbers is not

Given that, ⇒ 7 - 18 = - 11 ⇒ 7 - 18 - 5 = - 11 - 5 = - 16 .....(i) ⇒ 18 - 5 = 13 ⇒ 7 - 18 - 5 = 7 - 13 = - 6 .....(ii) From equation (i) and (ii), 7 - 18 - 5 ≠ 7 - 18 - 5 For any three whole numbers x , y and z . x - y - z ≠ y - z So, the subtraction of whole numbers is not associative. Therefore, 7 - 18 - 5 ≠ 7 - 18 - 5 and the subtraction of whole numbers is not associative

12 × 9 - 6 = _ _ _ _ _ = _ _ _ _ _

Given that, To evaluate 12 × 9 - 6 = _ _ _ _ _ = _ _ _ _ _ . Use BODMAS rule to evaluate 12 × 9 - 6 = _ _ _ _ _ = _ _ _ _ _ . According to BODMAS, the order of preference is brackets, division, multiplication, addition and subtraction. According to BODMAS, evaluate the operations in the brackets first. ⇒ 12 × 9 - 6 = 12 × 3 Find the value of 12 × 3 . After simplifying the numbers in brackets, perform other operations like multiplication. ⇒ 12 × 3 = 36 Therefore, the evaluation of 12 × 9 - 6 = 12 × 3 = 36 .

12 × 9 - 12 × 6 = _____ = _____

Given that, To evaluate 12 × 9 - 12 × 6 = _____ = _____ Use BODMAS rule to evaluate 12 × 9 - 12 × 6 = _____ = _____ According to BODMAS, the order of preference is brackets, division, multiplication, addition and subtraction. According to BODMAS, simplify the multiplication part first. ⇒ 12 × 9 - 12 × 6 = 108 - 72 Find the value of 108 - 72 . After simplifying the multiplication part, perform other operations like subtraction. ⇒ 12 × 9 - 12 × 6 = 108 - 72 ⇒ 12 × 9 - 12 × 6 = 36 Therefore, the evaluation of 12 × 9 - 12 × 6 = 108 - 72 = 36 .

16 - 8 × 24 = _____ = _____

Given that, To evaluate 16 - 8 × 24 = _____ = _____ Use BODMAS rule to evaluate 16 - 8 × 24 = _____ = _____ According to BODMAS, the order of preference is brackets, division, multiplication, addition and subtraction. According to BODMAS, evaluate the operations in the brackets first. ⇒ 16 - 8 × 24 = 8 × 24 Find the value of 8 × 24 . After simplifying the numbers in brackets, perform other operations like multiplication. ⇒ 8 × 24 = 192 Therefore, the evaluation of 16 - 8 × 24 = 8 × 24 = 192 .

16 × 24 - 8 × 24 = _____ = _____

Given that, To evaluate 16 × 24 - 8 × 24 = _____ = _____ Use BODMAS rule to evaluate 16 × 24 - 8 × 24 = _____ = _____ According to BODMAS, the order of preference is brackets, division, multiplication, addition and subtraction. According to BODMAS, simplify the multiplication part first. ⇒ 16 × 24 - 8 × 24 = 384 - 192 Find the value of 384 - 192 . After simplifying the multiplication part, perform other operations like subtraction. ⇒ 16 × 24 - 8 × 24 = 384 - 192 ⇒ 16 × 24 - 8 × 24 = 192 Therefore, the evaluation of 16 × 24 - 8 × 24 = 384 - 192 = 192 .

Is ( 16 - 8 ) × 24 = 16 × 24 - 8 × 24 .

Given that, To find whether ( 16 - 8 ) × 24 = 16 × 24 - 8 × 24 . According to BODMAS, the order of preference is brackets, division, multiplication, addition and subtraction. L.H.S: Refer 6 ( a ) . ⇒ ( 16 - 8 ) × 24 = 8 × 24 ⇒ ( 16 - 8 ) × 24 = 192 ..... ( i ) R.H.S: Refer 6 ( b ) . ⇒ 16 × 24 - 8 × 24 = 384 - 192 ⇒ 16 × 24 - 8 × 24 = 192 ..... ( i i ) From equations ( i ) and ( i i ) , ⇒ ( 16 - 8 ) × 24 = 16 × 24 - 8 × 24 Therefore, ( 16 - 8 ) × 24 = 16 × 24 - 8 × 24 and is equal to 192 .

16 - 8 × 24 = 16 × 24 - 8 × 24 = 192 Is this type of result always true?

Given that, To identify whether the type of result of the form 16 - 8 × 24 = 16 × 24 - 8 × 24 are always true. The given equation is of the form a - b × c = a × c - b × c . Take examples: Let a = 5 , b = 3 , c = 2 . ⇒ 5 - 3 × 2 = 5 × 2 - 3 × 2 ⇒ 2 × 2 = 10 - 6 ⇒ 4 = 4 Let a = 6 , b = 5 , c = 2 . ⇒ 6 - 5 × 2 = 6 × 2 - 5 × 2 ⇒ 1 × 2 = 12 - 10 ⇒ 2 = 2 So, from the above examples, it can be stated that a - b × c = a × c - b × c is true. Therefore, this type of result is always true.

E M B I B E

Concise Mathematics Middle School Class 6>Chapter 5 - Natural Numbers and Whole Numbers>EXERCISE

R K Bansal Solutions for Chapter: Natural Numbers and Whole Numbers, Exercise 1: EXERCISE

Author:R K Bansal

R K Bansal Mathematics Solutions for Exercise - R K Bansal Solutions for Chapter: Natural Numbers and Whole Numbers, Exercise 1: EXERCISE

Attempt the free practice questions on Chapter 5: Natural Numbers and Whole Numbers, Exercise 1: EXERCISE with hints and solutions to strengthen your understanding. Concise Mathematics Middle School Class 6 solutions are prepared by Experienced Embibe Experts.