Evaluate : 2 2 + 3 2 × 1 2 2

Given, 2 2 + 3 2 × 1 2 2 = 4 + 9 × 1 4 = 13 4 = 3 1 4 Therefore, 2 2 + 3 2 × 1 2 2 = 3 1 4

Evaluate: 5 2 - 3 2 × 2 3 - 3

Given, 5 2 - 3 2 × 2 3 - 3 = 25 - 9 × 3 2 3 = 16 × 27 8 = 54 Therefore, 5 2 - 3 2 × 2 3 - 3 = 54

Evaluate: 1 4 - 3 - 1 3 - 3 ÷ 1 6 - 3

Given, 1 4 - 3 - 1 3 - 3 ÷ 1 6 - 3 = 4 3 - 3 3 ÷ 6 3 = 64 - 27 ÷ 216 = 37 ÷ 216 = 37 216 Therefore, 1 4 - 3 - 1 3 - 3 ÷ 1 6 - 3 = 37 216

Evaluate: - 3 4 - 2 2

Given, - 3 4 - 2 2 = - 3 4 - 4 = 4 - 3 4 = 256 81 Therefore, - 3 4 - 2 2 = 256 81

Evaluate: 3 5 - 2 - 2

Given, 3 5 - 2 - 2 = 3 5 - 2 × - 2 = 3 5 4 = 81 625 Therefore, 3 5 - 2 - 2 = 81 625

Evaluate: 5 - 1 × 3 - 1 ÷ 6 - 1

Given, 5 - 1 × 3 - 1 ÷ 6 - 1 = 1 5 × 1 3 ÷ 1 6 = 1 15 × 6 = 2 5 Therefore, 5 - 1 × 3 - 1 ÷ 6 - 1 = 2 5

If 1125 = 3 m × 5 n , find m and n .

Given, 1125 = 3 m × 5 n 3 1125 3 375 5 125 5 25 5 5 1 ∴ 1125 = 3 × 3 × 5 × 5 × 5 = 3 2 × 5 3 Thus, 3 2 × 5 3 = 3 m × 5 n Hence, m = 2 and n = 3

Find x , if 9 × 3 x = 27 2 x - 3 .

Given, 9 × 3 x = 27 2 x - 3 ⇒ 3 2 × ( 3 ) x = 3 3 2 x - 3 ⇒ 3 2 + x = 3 6 x - 9 ⇒ 2 + x = 6 x - 9 ⇒ 2 + 9 = 6 x - x ⇒ 5 x = 11 ⇒ x = 11 5 Hence, x = 11 5

E M B I B E

Concise Mathematics Middle School Class 8>Chapter 2 - Exponents (Powers)>EXERCISE 2(A)

R K Bansal Solutions for Chapter: Exponents (Powers), Exercise 1: EXERCISE 2(A)

Author:R K Bansal

R K Bansal Mathematics Solutions for Exercise - R K Bansal Solutions for Chapter: Exponents (Powers), Exercise 1: EXERCISE 2(A)

Attempt the practice questions on Chapter 2: Exponents (Powers), Exercise 1: EXERCISE 2(A) with hints and solutions to strengthen your understanding. Concise Mathematics Middle School Class 8 solutions are prepared by Experienced Embibe Experts.