R S Aggarwal Solutions for Exercise 1: EXERCISE

The equation of a hyperbola is $\frac{y^2}{4}-\frac{x^2}{9}=1$

Length of its transverse axis =_____units.

The equation of a hyperbola is $\frac{y^2}{4}-\frac{x^2}{9}=1$

Length of its conjugate axis =_____units.

The equation of a hyperbola is $\frac{y^2}{4}-\frac{x^2}{9}=1$

Its eccentricity,$e$ is of the form of $\frac{\sqrt{x}}{y}$, then $x+y=$_____

The equation of a hyperbola is $\frac{y^2}{4}-\frac{x^2}{9}=1$

Length of its latus rectum =_____units.

The vertices of a hyperbola are $(0,\pm 3)$ and its foci are $(0,\pm 5)$ . The equation of the hyperbola is

The vertices of a hyperbola are $(0,\pm 6)$ and its eccentricity is $\frac{5}{3}·$ The equation of the hyperbola is

One focus of a hyperbola is at $(0,4)$ and the length of its transverse axis is $6$ The equation of the hyperbola is

Foci of a hyperbola are $(0,\pm 6)$ and the length of its conjugate axis is $2\sqrt{11}$. The equation of the hyperbola is