R S Aggarwal Solutions for Exercise 1: EXERCISE 6A

If $\frac{5x+8}{4-x}<2, x\in R$ is $(-\infty ,k)\cup [a,\infty )$, then find $a+k$.

If $|3x-7|>4, x\in R$ is $(-\infty ,k)\cup \left(\frac{11}{3},\infty \right)$, then find $k$.

If the solution of the following equation $|5-2x|\le 3, x\in R$ is $\left[1,k\right]$, then find $k$.

If the solution of the equation $|4x-5|\le \frac{1}{3}, x\in R$ is $\left[\frac{7}{6},\frac{k}{3}\right]$, then find $k$.

If the solution of the equation $\frac{1}{\left|x\right|-3}\le \frac{1}{2},x\in R$ is $(-\infty ,a]\cup (-3,3)\cup [k,\infty )$, find $a+k$.

If the solution of the equation $\frac{|x-3|-x}{x}<2, x\in R$ is $\left(-\infty ,k\right)\cup \left(1,\infty \right)$, then find $k$.

If the solution of $\left|\frac{2x-1}{x-1}\right|>2,x\in R$ is $\left(\frac{3}{4},k\right)\cup \left(1,\infty \right)$, then find $k$

If the solution of $\frac{|x-3|}{x-3}>0,x\in R$ is $\left(k,\infty \right)$, then find $k$.