R S Aggarwal and Veena Aggarwal Solutions for Exercise 2: Exercise 3B

Find $\mathrm{x}+\mathrm{y}$ if $\frac{\mathrm{x}}{2}-\frac{\mathrm{y}}{9}=6$ and $\frac{\mathrm{x}}{7}+\frac{\mathrm{y}}{3}=5$.

If $\frac{\mathrm{x}+\mathrm{y}-8}{2}=\frac{\mathrm{x}+2\mathrm{y}-14}{3}=\frac{3\mathrm{x}+\mathrm{y}-12}{11}$, then $x, y=$ __ , __

Solve for $\mathrm{x}$ and $\mathrm{y}$:

$\frac{1}{2\mathrm{x}}+\frac{1}{3\mathrm{y}}=2$

$\frac{1}{3\mathrm{x}}+\frac{1}{2\mathrm{y}}=\frac{13}{6}$

Solve for $\mathrm{x}$ and $\mathrm{y}$ and find the sum of $x$ and $y$.

$\frac{3}{\mathrm{x}+\mathrm{y}}+\frac{2}{\mathrm{x}-\mathrm{y}}=2,\frac{9}{\mathrm{x}+\mathrm{y}}-\frac{4}{\mathrm{x}-\mathrm{y}}=1$, where $\mathrm{x}+\mathrm{y}\ne 0$ and $\mathrm{x}-\mathrm{y}\ne 0$

Solve for $x$ and $y$

$x+y=a+b, ax-by=a^2-b^2$

Solve for $x$ and $y$:
$$\begin{gathered} 6(ax+by)=3a+2b \\ 6(bx-ay)=3b-2a \end{gathered}$$

Solve for $x$ and $y$:

$ax-by=a^2+b^2, x+y=2a$

Solve for $x$and $y$:

$a^{2}x+b^{2}y=c^2, b^{2}x+a^{2}y=d^2$