Find the inclination of a line whose slope is 3 .

Let ' m ' be the slope of the required line. And θ is the inclination of the line. We know that, the slope of line with inclination θ is m = tan θ . The slope of the given line is 3 . ⇒ 3 = tan θ ⇒ tan θ = tan 60 0 ⇒ θ = 60 0 Hence, the inclination of the line is 60 0 .

Find the inclination of a line whose slope is 1 3 .

Let ' m ' be the slope of the required line. And θ is the inclination of the line. We know that, the slope of line with inclination θ is m = tan θ . The slope of the given line is 1 3 . ⇒ 1 3 = tan θ ⇒ θ = tan - 1 1 3 ⇒ θ = tan - 1 tan 30 0 ∵ tan - 1 tan θ = θ , - π 2 < θ < π 2 ⇒ θ = 30 0 Hence, the inclination of the line is 30 0 .

Find the inclination of a line whose slope is − 3 .

Let ' m ' be the slope of the required line. And θ is the inclination of the line. We know that, the slope of line with inclination θ is m = tan θ . The slope of the given line is - 3 . ⇒ - 3 = tan θ ⇒ tan θ = - tan 60 0 ⇒ tan θ = tan 180 0 - 60 0 ∵ tan 180 ° - θ = - tan θ ⇒ tan θ = tan 120 0 ⇒ θ = 120 0 Hence, the inclination of the line is 120 0 .

E M B I B E

WBCHSE Mathematics for Class 11>Coordinate Geometry>Chapter 16 - Straight Lines>EXERCISE 1B

R S Aggarwal Solutions for Exercise 2: EXERCISE 1B

Author:R S Aggarwal

R S Aggarwal Mathematics Solutions for Exercise - R S Aggarwal Solutions for Exercise 2: EXERCISE 1B

Attempt the practice questions from Exercise 2: EXERCISE 1B with hints and solutions to strengthen your understanding. WBCHSE Mathematics for Class 11 solutions are prepared by Experienced Embibe Experts.