R. D. Sharma Solutions for Chapter: Quadratic Equations, Exercise 9: EXERCISE 4.9

The sum of ages of a man and his son is $45 \mathrm{years}$. Five years ago, the product of their ages was four times the man's age at the time. Find their present ages.

The product of Shikha's age five years ago and her age $8 \mathrm{years}$ later is $30,$ her age at both times being given in years. Find her present age.

The product of Ramu's age (in years) five years ago and his age (in years) nine years later is $15$. Determine Ramu's present age.

Is the following situation possible? If so, determine their present ages.

The sum of the ages of two friends is $20 \mathrm{years}$. Four years ago, the product of their ages in years was $48.$

A girl is twice as old as her sister. Four years hence, the product of their ages (in years) will be $160$. Find their present ages.

The sum of the reciprocals Rehman's ages$3$ years ago and five years from now is $\frac{1}{3}$. Find his present age.

If Zeba were younger by $5$ years than what she really is, then the square of her age (in years) would have been $11$ more than $5$ times her actual age. What is her age now?

At present Asha's age (in years) is $2$ more than the square of her daughter Nisha's age. When Nisha grows to her mother's present age, Asha's age would be one year less than $10$ times the present age of Nisha. Find the present ages of both Asha and Nisha.