R. Gupta Solutions for Chapter: Numbers, Exercise 1: EXERCISE

If $(x^2+\frac{1}{x^2})=66$ then $\left(x-\frac{1}{x}\right)$ is equal no.

If $a+b=8, a-b=4,$then $a^2+b^2$ is equal to :

If $x^2+5x-2k$ is exactly divisible by $(x-1)$, then the value of $k$ is:

If $(x-2)$ is a factor of $x^2+4x-2k$, then the value of $k$ is :

If $x^{100}+2x^{99}+k$ is divisible by $(x+1)$, then the value of k is :

Value of $k$ for which $(x-2)$ is a factor $(x^2-kx+2)$ is :

If $x-\frac{1}{x}=3$, the value of $x^2+\frac{1}{x^2}$ is:

If $x-\frac{1}{x}=2$ then $x^3-\frac{1}{x^3}$ is :