R. S. Aggarwal Solutions for Chapter: Volume and Surface Area, Exercise 1: EXERCISE 24A
R. S. Aggarwal Quantitative Aptitude Solutions for Exercise - R. S. Aggarwal Solutions for Chapter: Volume and Surface Area, Exercise 1: EXERCISE 24A
Attempt the free practice questions on Chapter 24: Volume and Surface Area, Exercise 1: EXERCISE 24A with hints and solutions to strengthen your understanding. Arithmetic Subjective and Objective for Competitive Examinations solutions are prepared by Experienced Embibe Experts.
Questions from R. S. Aggarwal Solutions for Chapter: Volume and Surface Area, Exercise 1: EXERCISE 24A with Hints & Solutions
What is the weight of water contained in a conical vessel of diameter and height ?

A solid metallic sphere of radius is melted and recast into small spheres of equal radii. The radius of each one of these spheres is :

Two metallic balls and are such that the diameter of is twice the diameter of . What is the ratio between the volumes of and ?

There are some solid metallic right circular cones, each of radius and height . These are melted and recast into a solid sphere of radius . The number of these cones is:

The volumes of two cones are in the ratio and their diameters are in the ratio . Their heights are in the ratio:

A solid metallic sphere of radius is melted and moulded into small right circular cones, each having as radius of the base and height. The number of such cones is

The radius of the base of a right circular cone is and its curved surface area is . The volume of the cone is :

The diameter of a cylindrical vessel is . It contains some water. On immersing an iron sphere fully in it, water level rises by . What is the radius of the sphere ?
