R.K. Singh Solutions for Chapter: Trigonometry, Exercise 2: Previous Years Questions

If $\tan \mathrm{\theta }-\cot \mathrm{\theta }=\mathrm{a}$ and $\cos \mathrm{\theta }+\sin \mathrm{\theta }=\mathrm{b}$, then the value of $\left({\mathrm{a}}^2+4\right){\left({\mathrm{b}}^2-1\right)}^2$ is:

If ${\mathrm{x}}^2+{\mathrm{y}}^2=1$, then the maximum value of $\mathrm{xy}$:

The maximum value of ${\sin }^6 \mathrm{\theta }+{\cos }^6 \mathrm{\theta }$ is:

If $\mathrm{\alpha }+\mathrm{\beta }=90°$ and $\mathrm{\alpha }=2\mathrm{\beta }$, then ${\cos }^2 \mathrm{\alpha }+{\sin }^2 \mathrm{\beta }$ is equals to:

$(\tan \mathrm{\theta }+\sec \mathrm{\theta }{)}^2$ is equals to:

If $\mathrm{\theta }=30°$ then the value of $\frac{1}{1+\cos \mathrm{\theta }}+\frac{1}{1-\cos \mathrm{\theta }}$ is:

If $cosec\mathrm{A}=2$, then $\frac{1}{\mathrm{tanA}}+\frac{\mathrm{sinA}}{(1+\mathrm{cosA})}=?$

The angle of elevation of tower at a point is such that the value of its tan is $\frac{5}{12}$, on moving $240 \mathrm{m}$ towards the tower its value of tan of angle of elevation becomes $\frac{3}{4}$. Then the height of the tower is: