R.K. Singh Solutions for Chapter: SSC Advanced Maths. : Previous Years Solved Papers, Exercise 14: SSC CGL Tier-II Exam. : 29.09 .2013

The areas of two similar triangles are $360{ \mathrm{cm}}^2$ and $250 {\mathrm{cm}}^2$. If one side of one triangle is $8 \mathrm{cm}$ long, then find the length of the corresponding side of the other triangle.

In$∆\mathrm{ABC}, \angle \mathrm{ABC}=5\angle \mathrm{ACB}$ and $\angle \mathrm{BAC}=3\angle \mathrm{ACB}$ then $\angle \mathrm{ABC}=?$

If $\mathrm{a}=\frac{{\mathrm{b}}^2}{\mathrm{b}-\mathrm{a}}$, then ${\mathrm{a}}^3+{\mathrm{b}}^3$ is equal to:

The number of solutions of equations $4\mathrm{x}-\mathrm{y}=2$ and $2\mathrm{y}-8 \mathrm{x}+4=0$ is:

If ${\mathrm{a}}^2+{\mathrm{b}}^2+{\mathrm{c}}^2=2(\mathrm{a}-\mathrm{b}-\mathrm{c})-3$ then $2 \mathrm{a}-3 \mathrm{b}+4 \mathrm{c}$ is equal to:

The equation ${\cos }^2\mathrm{\theta }=\frac{(\mathrm{x}+\mathrm{y}{)}^2}{4\mathrm{xy}}$ is possible only when:

Which one is large $\sqrt[3]{2}$ or $\sqrt{3}?$

If $\mathrm{a}+\mathrm{b}+\mathrm{c}=9$ (where $\mathrm{a}, \mathrm{b}, \mathrm{c}$ are real), then the minimum value of ${\mathrm{a}}^2+{\mathrm{b}}^2+{\mathrm{c}}^2$.